Answer: 0.345
Step-by-step explanation:
Given : The incomes of families in Newport Harbor are normally distributed with Mean : 
and Standard deviation : 
Samples size : n=4
Let x be the random variable that represents the incomes of families in Newport Harbor.
The z-statistic :-
For x= $800,000
By using the standard normal distribution table , we have
The probability that the average income of these 4 families exceeds $800,000 :-
Hence, the probability that the average income of these 4 families exceeds $800,000 =0.345
Answer: the answer is SSS I hope this is what u asked for let me now if it wasn't Have a great night :)
Step-by-step explanation:
Step-by-step explanation: look so if you have
shcool A its 8v+4b=12
and
School B: 12v+4b= 16
since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.
You should find part of the process to be
12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.
Answer -4
-6 = y/5 + 4
Step 1: Subtract 4 from each side of the equation.
Step 2: Multiply each side by 5.
If you don't arrive at the solution y= -50 , then return to Step-1
and repeat the process, being on the lookout for your mistake.
