How do I graph the equation?

Mathematics

1 answer:

makvit [3.9K]3 years ago

4 0

The equation is y=2.5x.
Let the y axes increase by 2.5 and the x axes by ones

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If the sides of a parallelogram are increased to twice its original lengths, how much will the perimeter of the new parallelogra

inna [77]

Answer:

2 times

Step-by-step explanation:

the length and breadth of the parallelogram will be l and b, respectively.

Then, perimeter = 2(1 + b) [∵ perimeter of parallelogram = 2 x (length + breadth)]

If both sides are increased twice, then new length and breadth will be 21 and 2b, respectively.

Now, new perimeter = 2(21 + 2b) = 2 x 2(l + b) = 2 times of original perimeter.

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What is 1 4/5 + 2 3/20 +5/ 3

sveticcg [70]

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3 years ago

Find the Taylor series for f(x)=sin(x) centered at c=π/2.sin(x)=∑ n=0 [infinity]On what interval is the expansion valid? Give yo

agasfer [191]

Answer:

sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...

Step-by-step explanation:

given that f(x) = sin x

we have to find the Taylor series for that

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and so on.

i.e. 2nd, 4th, 6th terms would be 0

and also 1st, 5th, 9th terms would be positive for f value and 3rd, 9th,... would be negative

Using the above we can write Taylor series as

$f(x) = f(a)+\frac{f'(a)}{1!} (x-\frac{\pi}{2}) +...+f^n(a) /n! (x- \frac{\pi}{2})^n+...$

$sinx =1-\frac{1}{2} (x-\frac{\pi}{2} )^2+\frac{1}{24} (x-\frac{\pi}{2} )^4-\frac{1}{720} (x-\frac{\pi}{2} )^6+\frac{1}{40320} (x-\frac{\pi}{2} )^8+...$