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valentinak56 [21]
3 years ago
12

HELP!!!! PLEASE!!!!!!!

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

I cant really see the questions

Step-by-step explanation:

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What is average unit rate for 200/12.54
Nadusha1986 [10]

Answer:

Approximately 16.

Step-by-step explanation:

If you just divide 200/12.54, you get about 15.9 which rounds to 16.

3 0
3 years ago
Y = 5- 2<br> 1-3x + y = -12<br><br> What is the value of x and y ?
zloy xaker [14]

Answer:

x=5.333

y=3

Step-by-step explanation:

given, y=5-2............(1)

1-3x+y=-12...............(2)

y=5-2=3

put y=3 in equ (2)

1-3x+3=-12

1+3+12=3x

3x=16

x=\frac{16}{3}

x=5.333

hence, x=5.333

           y=3               answer

7 0
3 years ago
01
aev [14]
The is The 103.8 Cause Of the math is correct
4 0
3 years ago
Is 143 a prime number
tensa zangetsu [6.8K]
143 is composite. To be prime it has to have only 2 divisors i.e it's self and one but since it has 4 divisors ( 143, 1, 11 and 13) it is composite.
5 0
3 years ago
Read 2 more answers
Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent
goblinko [34]

Answer:

y(x)=x^2+5x

Step-by-step explanation:

Given: y'=\sqrt{4y+25}

Initial value: y(1)=6

Let y'=\dfrac{dy}{dx}

\dfrac{dy}{dx}=\sqrt{4y+25}

Variable separable

\dfrac{dy}{\sqrt{4y+25}}=dx

Integrate both sides

\int \dfrac{dy}{\sqrt{4y+25}}=\int dx

\sqrt{4y+25}=2x+C

Initial condition, y(1)=6

\sqrt{4\cdot 6+25}=2\cdot 1+C

C=5

Put C into equation

Solution:

\sqrt{4y+25}=2x+5

or

4y+25=(2x+5)^2

y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}

y(x)=x^2+5x

Hence, The solution is y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4} or y(x)=x^2+5x

4 0
3 years ago
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