For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have
Shape Tessellate?
Octagon No
Hexagon Yes
Pentagon No
Square Yes
Triangle No(unless it is specified that it is an equilateral triangle)
Place the right angle at the origin. Short leg on x-axis.
The forth corner of the square is the point on the hypotenuse where the line y = x intersects. (Draw a diagram!)
In this case the hypotenuse is y = -4x/3 + 8
x = -4x/3 + 8
7x/3 = 8
7x = 24
x = 3.428571429
For one pair of socks you pay $12 plus $2 shipping.
Let's use x as the variable for how many pairs of socks someone might buy.
If someone buys 5 pairs of socks, they will pay $62. $12 * 5 + $2
So, we can write the expression as 12x + 2.
Answer:
d=2.5
Step-by-step explanation:
first find the coordinate of B(mid point of AC):A(3,7) C(6,11)
d=√(6-3)²+(11-7)²
d=√3²+4²
d=√9+16=√25=5
since B is the mid point : d/2=5/2=2.5
<h2>Another way :</h2>
B(x1+x2/2 , y1+y2/2) , x1=3 , x2=6, y1=7, y2=11
B(9/2,18/2)
B(9/2,9)
Find AB : the length or distance between 2 points:
d=√(x2-x1)²+(y2-y1)²
d=√(3-9/2)²+(7-9)²
d=√(-3/2)²+(-2)²
d=√1.5²+4
d=√6.25
d=2.5
No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.
Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have
and since the relation of order "<" is transitive, this implies
