I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Might be A not sure though
Answer:
B and F
Step-by-step explanation:
Given
x² + 4x + 4 = 12 ( subtract 4 from both sides )
x² + 4x = 8
Using the method of completing the square to solve for x
add ( half the coefficient of the x- term )² to both sides
x² + 2(2)x + 4 = 8 + 4, that is
(x + 2)² = 12 ( take the square root of both sides )
x + 2 = ± 
( subtract 2 from both sides )
x = ± - 2
= ± 2
- 2
Hence
x = 2 - 2 → B
x = - 2 - 2 → F
Answer:
Segment BC = 36 mm or 3.6 cm
Step by Step Explanation:
There are 10 mm in 1 cm
meaning that segment AC is 40 mm long
if AB is 4 mm and it is one part of the two, then we need to subtract that from the total to find out what is left.
40 - 4 = 36
Segment BC = 36 mm or 3.6 cm
