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Mathematics

1 answer:

natta225 [31]2 years ago

8 0

Answer: it would be (2, -4) because if you flip it it will still be the same just at a different angle.

Step-by-step explanation:

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Find The art length of a sector with an area of 8 square units.

frez [133]

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
A=8\\
r=4
\end{cases}\implies 8=\cfrac{\theta \pi 4^2}{360}\implies \cfrac{8\cdot 360}{4^2\pi }=\theta 
\\\\\\
\cfrac{2880}{16\pi }=\theta \implies \boxed{\cfrac{180}{\pi }=\theta }\\\\
-------------------------------\\\\$

$\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
\theta =\frac{180}{\pi }\\
r=4
\end{cases}\implies s=\cfrac{\frac{180}{\underline{\pi} }\underline{\pi} \cdot 4}{180}\implies s=\cfrac{\underline{180}\cdot 4}{\underline{180}}
\\\\\\
\boxed{s=4}$

if you do a quick calculation on what that angle is, you'll notice that it is exactly 1 radian, and an angle of 1 radian, has an arc that is the same length as its radius.

that's pretty much what one-radian stands for, an angle, whose arc is the same length as its radius.

6 0

3 years ago

Find "both answers.

amid [387]

Sorry yo i just need points :/

5 0

2 years ago

The motorcycle engine on a kawasaki ninja 1000 has a displacement of 1043 cubic-centimeters (cm3). in order to calculate its eng

marishachu [46]

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

<h3>Further explanation</h3>

We will calculate the unit conversion factor used to convert its engine displacement from cubic-centimeters to cubic-inches.

The relationships between inch and cm are as follows:

$\boxed{ \ 1 \ inch = 2.54 \ cm\ }$

Inches and cm represent units of length.

Made into fractions, 1 inch as the denominator and 2.54 cm as the numerator.

$\boxed{ \ \frac{1 \ inch}{2.54 \ cm} \ }$

As a unit conversion factor of volume, the numerator and the denominator in cubic.

$\boxed{ \ \frac{(1 \ inch)^3}{(2.54 \ cm)^3} \ }$

$\boxed{ \ \frac{1 \ inch^3}{16.387 \ cm^3} \ }$

Thus, we get the unit conversion factor

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

Let's use this unit conversion factor to calculate its engine displacement in new units.

$\boxed{= 1,043 \ cm^3 \times 0.061 \ \frac{inch^3}{cm^3}}$

Note for cm³ units that have been crossed out.

The conversion result is $\ \boxed{ \ 63.623 \ inch^3\ }$

<h3>Learn more</h3>

Convert cubic-kilometers to cubic-meters brainly.com/question/1446243
How to write in scientific notation brainly.com/question/7263463
Calculating mass based on density and volume brainly.com/question/4053884

Keywords: the motorcycle engine, Kawasaki Ninja 1000, 1043 cubic-centimeters (cm³), to calculate, its engine displacement, in cubic-inches (in³), what unit conversion factor