All categories

3 years ago

PLEASE HELP DUE IN 3 minutes

Mathematics

2 answers:

just olya [345]3 years ago

5 0

Answer: the second one from the top

Step-by-step explanation:

the diagram is basically turned on the side 0-4 is on the bottom instead of the side the numbers on the right are on top of the numbers that were on the left

son4ous [18]3 years ago

3 0

Answer:

2....................

You might be interested in

At RSM summer camp 100 students had enough food for a 30-days stay. After 2 days 40 new students joined the camp. After that 2 w

omeli [17]

Answer:

"no additional days of food need to be ordered."

Step-by-step explanation:

Suppose initial quantity of food is x units

Assuming each student eats 1 unit of food per day,

x = 30 * 100 = 3000 units of food

In 2 days, food eaten:

100 * 1 * 2 = 200 units

So food left after 2 days is 3000 - 200 = 2800 units

Now, there are 140 students. They stay 2 weeks (14 days) - 2 = 12 more days

So food eaten in 12 days:

140 * 1 * 12 = 1680 units

<u>THus, after total 14 days gone, the amount of food left is:</u>

2800 - 1680 = 1120 units

Half students left, so there are 70 students left for the last 16 days. How much food would they need?

70 * 1 * 16 = 1120 units

And there are exactly 1120 units left. So, no additional days of food need to be ordered.

6 0

3 years ago

PLS HELP I HAVE LEGIT 20 MINUTES TO FINISH BY 11:59 IM PANICKING PLS HELP WITH THESE QUESTIONS

poizon [28]

I’m pretty sure it is 19.2 units

5 0

2 years ago

Read 2 more answers

The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr

Kobotan [32]

Answer:

% change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

$T = 2.5 x + 0.5 x^{2}$

We will approximate this distance using the relation

$f (x + dx) = f (x)+ f' (x)dx$

dx = 26 - 25 = 1

T' = 2.5 + x

Therefore

$f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x$

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× $25^{2}$ + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × $25^{2}$

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

% change in stopping distance = $\frac{27.5}{375}$ × 100

% change in stopping distance = 7.34 %

6 0

3 years ago

Dan is comparing the cost of having printed and prepared by two companies

Kay [80]

For 4 copies, the total cost for preparing and printing will be the same.

Step-by-step explanation:

Let,

p be the number of pages

Company A;

Charges of preparing = $6

Charges of per page print = $2.50

A(p)= 2.50p + 6 Eqn 1

Company B;

Charges of preparing = $4

Charges of per page print = $3

B(p)= 3p + 4 Eqn 2

For equaling the cost;

A(p) = B(p)

$2.50p+6=3p+4\\2.50p-3p=4-6\\-0.50p=-2$

Dividing both sides by -0.50

$\frac{-0.50p}{-0.50}=\frac{-2}{-0.50}\\p=4$

For 4 copies, the total cost for preparing and printing will be the same.

Keywords: Addition, division

Learn more about division at:

#LearnwithBrainly

8 0

3 years ago

* NOTICE THIS IS A 2 PART QUESTION

blondinia [14]

Answer: you would have to purchase $1300 of merchandise and the total yearly amount paid to the warehouse for each plan is $1210

Step-by-step explanation:

Let x represent the number of dollars of merchandise that you would have to purchase in a year to pay the same amount under both plans.

Plan A offers an annual membership fee of $300 and you pay 70%, of the manufacturers reccomended list price. This means that the total cost of using plan A would be

300 + 0.7x

Plan B offers an annual membership fee of $40 and you pay 90% of the manufacturers reccomended list price.

This means that the total cost of using plan B would be

40 + 0.9x

For both plans to be the same,

300 + 0.7x = 40 + 0.9x

0.9x - 0.7x = 300 - 40

0.2x = 260

x = $1300

The total yearly amount paid to the warehouse for each plan would be

40 + 0.9 × 1300 = $1210

6 0

3 years ago