Question

I need help on the bottom problem

Answer 1

Divide each term by 4x:

$\sf\dfrac{96x^3+36x^2+4x-1}{4x}$

$\sf\dfrac{96x^3}{4x}+\dfrac{36x^2}{4x}+\dfrac{4x}{4x}-\dfrac{1}{4x}$

Just divide them separately.

96/4 = 24
x^3/x = x^2
So our first term is 24x^2.

36/4 = 9
x^2/x = x
So our second term is 9x.

4x/4x = 1
Anything divided by itself is 1. This is our 3rd term.

-1/4x, we can't simplify this any further, so this is our last term.

So we have:

$\boxed{\sf 24x^2+9x+1-\dfrac{1}{4x}}$

Answer 2

96x^3/(4x) + 36x^2/(4x) + 4x/(4x) - 1/(4x)
You only have an error in the last term. It's actually a very good start.

24x^2 + 9x + 1 - 0.25/x is one way to do it. Or you could leave it as 1/4x. It depends on how this is marked. If it is a machine, take your best shot. If you get it wrong, there must be a person somewhere that understands what you meant. Appeal it.