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DIA [1.3K]
3 years ago
8

Kyle has 2 3/4 pounds of flour. He wants to divide the flour into 3 equal-sized

Mathematics
2 answers:
marta [7]3 years ago
6 0
About .92 lbs or 11/12 lbs in each bag
Yuri [45]3 years ago
4 0

Answer:

11/12

Step-by-step explanation:

All you do is make 2 3/4 a improper fraction and then divided the improper fraction by 3 to get 11/12

Hope it helps :D

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Use the elimination method to solve the system of equations.
ExtremeBDS [4]

Answer:

Option D. (8, – 4)

Step-by-step explanation:

3x + 4y = 8 ..... (1)

x – y = 12.... (2)

To solve the above equation by elimination method, do the following:

Step 1:

Multiply equation 1 by the coefficient of x in equation 2 i.e 1.

Multiply equation 2 by the coefficient of x in equation 1 i.e 3. This is illustrated below:

1 × Equation 1

1 × (3x + 4y = 8)

3x + 4y = 8 ...... (3)

3 × Equation 2

3 × ( x – y = 12)

3x – 3y = 36......(4)

Step 2:

Subtract equation 3 from equation 4. This is illustrated below:

. 3x – 3y = 36

– (3x + 4y = 8)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

– 7y = 28

Divide both side by the coefficient of y i.e –7

y = 28/–7

y = – 4

Step 3:

Substitute the value of y into any of the equation to obtain the value of x. In this case, we shall substitute the value of y into equation 2 as shown below:

x – y = 12

y = –4

x – (–4) = 12

x + 4 = 12

x = 12 – 4

x = 8

Therefore, the solution to the equation above is (8, – 4)

4 0
4 years ago
Please prove. hurry pls
scoray [572]
Where is the image at?
6 0
3 years ago
PLEASE HELP ASAP!!!!!!!
12345 [234]
6 to 10 10-6 = 4 that is the range
6 0
3 years ago
Read 2 more answers
Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com
kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in ^5C_4 = 5 ways.

The probability that any four among the 5 will come is 5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}.

The probability that all of the 5 passengers will come is \frac{1}{32}.

Hence, the required probability is \frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}.

(b)

The probability that there will be exactly 10 passengers on the flight is ^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}.

The probability that there will be no empty seats in the plane is \frac{3}{16} + \frac{5}{16} = \frac{1}{2}.

Hence, probability of having empty seats is 1 - \frac{1}{2} = \frac{1}{2}.

6 0
3 years ago
Pls help me with this
Valentin [98]

Answer:

24

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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