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3 years ago

If m is the midpoint of ab find the coordinates of a if b(4,6) and m(1,2) A is pls help I need to know pls

Mathematics

1 answer:

KiRa [710]3 years ago

4 0

A is (-2;2). Hope this helps

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Evaluate each expression.

KonstantinChe [14]

Answer:

Please check the explanation.

Step-by-step explanation:

Solving the expressions

given the expression

$\left(-7\right)+\:\left(-10\right)\:-\:5\:+2$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a$

$=\left(-7\right)-10-5+2$

$=-17-5+2$

$=-22+2$

$=-20$

$\left(-9\right)+4+\left(-8\right)-\left(-7\right)$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a$

$=-5+\left(-8\right)-\left(-7\right)$

$=-5-8-\left(-7\right)$

$=-13-\left(-7\right)$

$=-13+7$

$=-6$

$\left(-6\right)\:-\:\left(2\:\times \:4\right)\:-\:\left(-1\right)\:$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:$

$\left(-6\right)-\left(2\times \:4\right)-\left(-1\right)$

Calculate within parentheses

$=\left(-6\right)-8-\left(-1\right)$

$=-14-\left(-1\right)$

$=-14+1$

$=-13$

10)

$\left(-8\right)\:+\:\left(-4\:\div \:-4\right)\:-\:8$

solving

$\left(-8\right)+\left(-\frac{4}{-4}\right)-8$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=-8-\frac{4}{-4}-8$

$=-8-\left(-1\right)-8$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=-8+1-8$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+1-8=-15$

$=-15$

5 0

3 years ago

Suppose we want to choose 3 letters, without replacement, from the 4 letters A, B, C, and D. (a) How many ways can this be done,

Aliun [14]

Answer:

A) 24 ways

B) 4 ways

Step-by-step explanation:

a) permutation occurrs when order of choices matters.

N = 4P3 = 4!/(4-3)! = 4!/1!

N = 24 ways

b) combination occurs when order of choices doesn't matter.

N = 4C3 = 4!/3!(4-3)! = 4!/3!(1!)

N = 4 ways

6 0

4 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

4 years ago

Two lines intersect and two of the vertical.angles measure 37 what is the measure of the other two vertical angles

Hoochie [10]

Lets start of with what we know.
• There are two 27 degree angles 27 + 27 = 52 is the sum of the angles.
•There are 360 degrees all around the intersection

So, we can find out the sum of the 2 angles that are unknown by subtracting.
360-52=308

So, if the sum of the unknown 2 angles are 308, we can divide by 2 to find the measure of the unknown angles.
308/2=154

4 0

3 years ago

Read 2 more answers

Multiply and simplify

MAVERICK [17]

Answer: The answer you clicked on in the picture is correct, (B)

Step-by-step explanation: I put the equation through a thing I know of (faMATHWAce) and got that as the answer.

8 0

4 years ago