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LenKa [72]
3 years ago
5

A cylindrical soup can has a radius of 8.4 cm and a height of 13.2 cm. What is the volume of the soup can to the nearest tenth o

f a cubic centimeter?
A= 110.9 cm3
B= 348.3 cm3
C= 673.8 cm3
D= 2926.1 cm3
Mathematics
1 answer:
Katarina [22]3 years ago
8 0

Answer:

D. 2926.1 cm3

Step-by-step explanation:

To calculate volume of a cylinder, you need to use the equation V = pi r² h, where r is radius and h is height.

you have the right numbers to plug in, so pi times 8.4² times 13.2, which gives you 2926.05 which you round up to 2926.1 cm³

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Given the coordinate points of the preimage, use the transformation given to provide the points of the image. W(3,3) V(3,4) U(5,
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Answer:

W'(-3,3) V'(-4,3) U'(-4,5)

Step-by-step explanation:

The mapping for 90 degrees counterclockwise rotation is;

(x,y)\to (-y,x)

The given points have coordinates: W(3,3) V(3,4) U(5,4)

(x,y)\to (-y,x)

This implies that:

W(3,3)\to W'(-3,3)

V(3,4)\to V'(-4,3)

U(5,4)\to U'(-4,5)

The required points of the image are:

W'(-3,3) V'(-4,3) U'(-4,5)

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Line g is dilated by a scale factor of 2 from the origin to create line g'. Where are points E' and F' located after dilation, a
saw5 [17]

Answer:

The points where E' and F' are located after dilation and how the lines g and g' are related are;

The locations E' and F' are E'(-8, 0) and F'(0, 4), and lines g and g' are parallel

Please see attached plot of lines g and g' created with MS Excel

Step-by-step explanation:

When an object is dilated by a scale factor, the length of the sides of the image formed is given as follows;

The length of the image = The length of the figure × The scale factor

The given parameters are;

The center of dilation = (0, 0) Dilated from the origin

The coordinates of the endpoint of the line 'g' = E(-4, 0), F(0, 2)

Therefore, we have;

The 'x', and 'y' coordinates of the point E' on the image from the center of dilation  (0, 0) = (-4 × 2, 0 × 2) = (-8, 0)

The 'x', and 'y' coordinates of the point F' on the image from the center of dilation  (0, 0) = (0 × 2, 2 × 2) = (0, 4)

Therefore, the coordinates of the point E' and F' on line g' = E'(-8, 0) and F'(0, 4)

Given that the proportion of the distances of E and E' to center of dilation (to the origin) and F and F' center of dilation are equal by the triangle proportionality theorem, EF is parallel to E'F' and the lines g and g' are said to be parallel

Therefore;

The coordinate of point E' = (-8, 0) and The coordinate of point F' = (0, 4)

Ling g is parallel to line g'

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3 years ago
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