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3 years ago

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Population of fruit flies has a mean life span of 46 days with a standard deviation of 6.2 days. If a sample of 30 fruit flies i

s taken from this population, what is the probability it will have a sample mean life span of greater than 48 days?

1 answer:

icang [17]3 years ago

7 0

Idk sorry I would answer if I did but I need points to ask a question

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1. Charlene makes $10 per hour babysitting and $5 per hour gardening. This week, she wants to make at least $80.

Lady_Fox [76]

Answer:

Step-by-step explanation:

Well is she wanted to make $80 “b” she would have to garden for 16 hours to make a maximum of $80

“C” if she wanted to make it out of babysitting she would have to work the same for 8 hours if she babysit

Workout : b part = 10+10+10+10+10+10+10+10 Key:10=2

:c part = 20+20+20+20. Key:20=2

Sorry I didn’t do a but just add all the things above and u get your answer

4 0

3 years ago

Show works please and do all of them for the 40 please because I need help

raketka [301]

Answer:

6 - Not similar

7 - Similar, 2x factor

8 - Similar, 3x factor

9 - Similar, 3x factor

10 - Not similar

11 - Similar, 5/3x factor

12 - x = 15

y = 25

z = 115

Step-by-step explanation:

8 0

3 years ago

What is the correct claim

djverab [1.8K]

Answer:

Claim 1

Step-by-step explanation:

4 0

3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers

The coldest temperature recorded in Alaska was –80°F. This was 10°F warmer than the coldest temperature recorded in Siberia. Whi

Klio2033 [76]

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10 = -80

Let the coldest temperature in Alaska be x

The coldest temperature recorded in Alaska was –80°F

x = –80°F

Let the coldest temperature in Siberia be y

The coldest temperature recorded in Alaska was 10°F warmer than the coldest temperature recorded in Siberia

This can be interpreted as:

Coldest temperature in Alaska = Coldest temperature in Siberia + 10

x = y + 10................(*)

Since x = -80

Substitute x = -80 into equation (*)

-80 = y + 10

This can be re-written as:

y + 10 = -80

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10 = -80

Learn more here: brainly.com/question/2159099

7 0

2 years ago