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3 years ago

How to graph and solve linear functions how to solve g(x)=-3x-1

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

I will explain the equation

in a graph, the slope will look like this

The Y Intercept is -1, and the slope is -3, as in it will go downward

For every 1x, the slope will go downward by 3.

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A sequence is defined recursively using the equation f(n + 1) = f(n) – 8. If f(1) = 100, what is f(6)?

BARSIC [14]

If the sequence f is defined as

$\mathsf{f(n+1)=f(n)-8}$

then

$\mathsf{f(n+1)-f(n)=-8}$

As you can see above, the difference between two consecutive terms gives us a constant.

So f is actually an arithmetic progression (AP), and it has (– 8) as its common difference:

$\mathsf{f(n)=f(1)+(n-1)\cdot d}\\\\ \textsf{where }\mathsf{d=-8.}$

• If f(1) = 100, then

$\mathsf{f(6)=f(1)+(6-1)\cdot (-8)}\\\\ \mathsf{f(6)=100+5\cdot (-8)}\\\\ \mathsf{f(6)=100-40}\\\\ \boxed{\begin{array}{l} \mathsf{f(6)=60} \end{array}}\qquad\checkmark$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2190444

I hope this helps. :-)

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3 years ago

I need help with 5&6 please ASAP!!!!!!!

Elenna [48]

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3 years ago

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Many stores run "secret sales": Shoppers receive cards that determine how large a discount they get, but the percentage is revea

Taya2010 [7]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Which expressions are equivalent to 6 (–x) 2x (–7) 2x? Check all that apply. X x 6 – 7 x 2x 2 x 3 – x 2x – 4 2x x – 1 x 1.

qaws [65]

Equivalent expression is the expression which is equal to the original equation but the way of representation is different. The equivalent expression of the given expression are,

$x+x+6-7+x$

$3-x+2x-4+2x=3x-1$

Given information

The given expression in the problem is,

$6+(-x)+2x+(-7)+2x$

<h3>Equivalent expression</h3>

Equivalent expression is the expression which is equal to the original equation but the way of representation is different.

The given equation is,

$6+(-x)+2x+(-7)+2x$

As the product of the negative and positive is negative. Thus solve the equation by opening the bracket.

$6+(-x)+2x+(-7)+2x=6-x+2x-7+2x\\
6+(-x)+2x+(-7)+2x=-x+2x+2x+6-7\\
6+(-x)+2x+(-7)+2x=3x-1$

Check all the option,

1) The expression given in the option 1 is,

$x+x+6-7+x$

Solve it further,

$x+x+6-7+x=x+x+x+6-7\\
x+x+6-7+x=3x-1\\$

The result is equal to the result of the given expression. Thus the expression of the option 1 is equivalent to the expression given in the problem.

2) The expression given in the option 2 is,

$2x+2+x$

Solve it further,

$2x+2+x=2x+x+2\\2x+2+x=3x+2$

The result is not equal to the result of the given expression. Thus the expression of the option 2 is not equivalent to the expression given in the problem.

3) The expression given in the option 3 is,

$3-x+2x-4+2x$

Solve it further,

$3-x+2x-4+2x=3x-1$

The result is equal to the result of the given expression. Thus the expression of the option 3 is equivalent to the expression given in the problem.

4) The expression given in the option 4 is,

$x-1$

The expression of the option 4 is not equivalent to the expression given in the problem.

5) The expression given in the option 4 is,

$x+1$

The expression of the option 5 is not equivalent to the expression given in the problem.

Hence the equivalent expression of the given expression are,

$x+x+6-7+x$

$3-x+2x-4+2x=3x-1$

Learn more about the equivalent expression here;

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2 years ago

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What are the solutions of 3x2 + 6x + 6 = 0?

AlladinOne [14]

The solutions or roots to this equation is found by solving for x. We can do this a couple ways either by FOIL or quad formula

3x^2+6x+6=0
3(x^2+2x+2)=0

x^2+2x+2=0 we cant FOIL this out so we use the quad formula

x= [(-b+\-sqrt(b^2-4ac))/2a]

x= -2+\- sqrt(4-4(1)(2))/2(1)
x= -1 +i , -1 - i

So we have complex roots since our quad formula returned a negative number. Whenever the quad formula answer is positive we have two roots/solutions, when it is zero we have one root/solution, and whenever it is negative we have Complex roots/solutions

Hope this helps. Any questions please just ask. Thank you.

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3 years ago