Since a line is equal to 180 degree
you pick one that has the variable x in it.
For example: 5x=180
180/5=36
therefore x=36
2. 6x=180
180/6= 30
x=30
Answer:
We have the system:
x ≤ 7
x ≥ a
Now we want to find the possible values of a such that the system has, at least, one solution.
First, we should look at the value of a where the system has only one solution:
We can write the 2 sets as:
a ≤ x
x ≥ 7
So, writing both together:
a ≤ x ≤ 7
if a is larger than 7, we do not have solutions.
then a = 7 gives:
7 ≤ x ≤ 7
Here the only solution is 7.
Now, if a is smaller than 7, for example 5, we have:
5 ≤ x ≤ 7
Now x can take different values, so we have a lot of solutions.
Then the restrictions for a, such that the system has at least one solution, is:
a ≤ 7.
Answer:
domain 10 range 9
Step-by-step explanation:
Answer:
C) 14
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other.
Multiply -2 to both sides of the equation. Note that, when multiplying two negative numbers, your outcome will be positive:
(-2)((-1/2)x) = (-7)(-2)
x = -7 * -2
x = 14
C) 14 is your answer.
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We find the inverse of equation y=x2-36 by solving for y and replace with variable x. Solving this, we transpose -36 to opposite side. Equation will now be y+36=x2, then we get the square root of y+36. We now have the missing inverse equation which is f−1(x)= sqrt (y+36), - sqrt (y+36).
