Answer:
The graph will begin on a lower point on the y-axis.
The y-values will continue to increase as x increases.
Step-by-step explanation:
Answer:
the radius of sphere X is 2 times larger than the radius of sphere T
Step-by-step explanation:
Given
Surface area of sphere, T =452.16
Surface area of sphere, X= 1808.64
how many times larger is the radius of sphere X than the radius of sphere T?
Finding radius of both spheres:
Surface area of sphere is given as
A=4πr^2
Now putting value of Ta=452.16 in above formula
452.16=4πrt^2
rt^2=452.16/4π
rt^2=35.98
Taking square root on both sides
rt=5.99
Now putting value of Xa=1808.64 in above formula
1808.64=4πrx^2
rx^2=1808.64/4π
rx^2=143.92
Taking square root on both sides
rx=11.99
Comparing radius of sphere X and the radius of sphere T
rx/rt=11.99/5.99
= 2.00
rx=2(rt)
Hence the radius of sphere X is 2 times larger than the radius of sphere T!
So volue of a cone=area of circle base times heigt times 1/3
height=4
area of base=pi times r^2
area of abse=aprox 3.14 times 3.2^2=32.1536
32.1536 times 4 times 1/3=32.1536 times 4/3=42.87 the amount of sand is 42.9 ft^3
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:
B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that 
. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then 
.
C) Consider 
. This set is orthogonal because 
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in 
. Then the columns of A form an orthonormal set. We have that 
. To see this, note than the component 
of the product 
is the dot product of the i-th row of 
and the jth row of 
. But the i-th row of is equal to the i-th column of . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then 
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set 
and suppose that there are coefficients a_i such that 
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then 
then 
.
kyle regalara 16 figuras y le quedara 3/4 de ellas
