(15.) A toy is in the shape of a cone mounted on a hemisphere of same base
1 answer:
Given:
Volume of toy=231 cm³
Diameter of a hemisphere= 7 cm
cone and hemisphere have equal radius.
radius of hemisphere = radius of cone = 3.5 cm
Height of hemisphere= radius of hemisphere= 3.5 cm
Let H be the height of toy
H= height of cone+ height of hemisphere
H = h + r , ( h = height of cone)
H = h + 3.5
volume of toy = volume of cone + volume of hemisphere
Volume of toy= 1/3πr²h + 2/3πr³
Volume of toy=πr²/3(h+2r)
231 = (22/7)×(3.5)² ×(1/3)(h+2×3.5)
231×3 =( 22×3.5×3.5)/7 (h+7)
h+7 = (231×3×7)/(3.5×3.5×22)
h+7 = (3×3)/(.5×.5×2)
h+7= 900 /50= 90/5= 18
h+7= 18
h=18-7
h= 11 cm
Height of toy = h+r
Height of toy = 11+3.5= 14.5
Height of toy =14.5 cm
Hence, the height of the toy = 13.5 cm
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Answer:
piip;[-p-o-ul0i
Step-by-step explanation: