Answer:
bro! im in 7th grade i would try to help but im very stupid sorry for the dissopiontment
Step-by-step explanation:
Answer:
not idea sorry but 4 no is idea it can be solve the 10 std
Answer:
b
Step-by-step explanation:
The answer is B.
Since ΔQRS ~ ΔXYZ, the value of tan(Q) is :
- ∠Q = ∠X
- tan(Q) = tan(X)
- tan(X) = 3/4
- tan(Q) = 3/4
When shifted to the right 1 unit it would be:
f(x - 1) = (x - 1)^3 + 2(x - 1)^2 - 3(x - 1) - 5
<span>= (x^3 - 3x^2 + 3x - 1) + 2(x^2 - 2x + 1) - 3(x - 1) - 5 </span>
<span>= x^3 - 3x^2 + 2x^2 + 3x - 4x - 3x - 1 + 2 + 3 - 5 </span>
<span>= x^3 - x^2 - 4x - 1
</span>I hope this helps
