Hey there !
As you've already mentioned all the necessary theory part , me will show the calculations and final answer ,
![\dfrac{1.09 \times {10}^{12} }{2.18 \times {10}^{10} } \: = \: \dfrac{ {10}^{2} }{2} = \dfrac{100}{2} = 50](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1.09%20%5Ctimes%20%7B10%7D%5E%7B12%7D%20%7D%7B2.18%20%5Ctimes%20%7B10%7D%5E%7B10%7D%20%7D%20%5C%3A%20%3D%20%5C%3A%20%5Cdfrac%7B%20%7B10%7D%5E%7B2%7D%20%7D%7B2%7D%20%3D%20%5Cdfrac%7B100%7D%7B2%7D%20%3D%2050)
Hence , 50 moons can fit inside earth
Hope it helps you :)
Answer:
Step-by-step explanation:
1/20 is a tiny portion of the length that needs to be traveled. 20/20 is the whole length. If 1/20 gets traveled in 3/4 of a second, multiply 3/4 by 20 to see how long it takes to travel 20(1/20) which is equal to 1, the whole path.
20(3/4) = 15 seconds
8 x 30 = 240ml
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Present age of Justin=14
Present age of Sam=11
<u>Step-by-step explanation:</u>
Let the present age of Sam=x
Given that Justin is 3 years older than Sam
present age of Justin=x+3
Age of Sam 3 years ago=x-3
Age of Justin two years hence=x+3+2=x+5
given that after 2 years Justin's age will be twice that of Sam's age three years ago
therefore
![x+5=2(x-3)x+5=2x-6\\5+6=2x-x=x\\11=x](https://tex.z-dn.net/?f=x%2B5%3D2%28x-3%29x%2B5%3D2x-6%5C%5C5%2B6%3D2x-x%3Dx%5C%5C11%3Dx)
Present age of Sam=x=11
Present age of Justin=x+3=11+3=14