Given :
A 2.8 m ladder is to be laid against a wall so that the top of the ladder is 2 m up the wall.
To Find :
How far out from the base of the wall should the ladder be placed.
Solution :
We know, the angle between floor and height is 90° .
Now, length of ladder, l = 2.8 m .
Height of wall, h = 2 m .
Let, distance between base of the wall and ladder is b .
Hence, this is the required solution.
Answer:
∠x = 78
Step-by-step explanation:
∠y + ∠1 = 180
=> 125 + ∠1 = 180
=> ∠1 = 180 - 125
=> ∠1 = 55
∠z + ∠2 = 360
=> 313 + ∠2 = 360
=> ∠2 = 360-313
=> ∠2 = 47
∠1 + ∠2 + ∠x = 180
=> 55 + 47 + ∠x = 180
=> ∠x = 180 - 55 - 47
=> ∠x = 78
Answer:
Step-by-step explanation:
We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.
We want to find the point on the line y=3x which is closest to Q.
Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.
If x=a, y=3a, so the point P has the coordinates (a,3a).
Distance between point Q and P
To minimize D, we find its derivative
Therefore, the y-coordinate for P is 3*6=18.
The point P=(6,18).
Next, we calculate the distance between P(6,18) and (60,0).