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sveta [45]
3 years ago
5

the volume of two similar solids are 1080cm and 1715cm .if the curved surface area of the smaller cone is 840cm .fond the curved

surface area of the larger cone​
Computers and Technology
1 answer:
gavmur [86]3 years ago
4 0

Answer:

A_{big} = 1143.33cm^2

Explanation:

The given parameters are:

V_{small} = 1080

V_{big} = 1715

C_{small} = 840

Required

Determine the curved surface area of the big cone

The volume of a cone is:

V = \frac{1}{3}\pi r^2h

For the big cone:

V_{big} = \frac{1}{3}\pi R^2H

Where

R = radius of the big cone and H = height of the big cone

For the small cone:

V_{small} = \frac{1}{3}\pi r^2h

Where

r = radius of the small cone and H = height of the small cone

Because both cones are similar, then:

\frac{H}{h} = \frac{R}{r}

and

\frac{V_{big}}{V_{small}} = \frac{\frac{1}{3}\pi R^2H}{\frac{1}{3}\pi r^2h}

\frac{V_{big}}{V_{small}} = \frac{R^2H}{r^2h}

Substitute values for Vbig and  Vsmall

\frac{1715}{1080} = \frac{R^2H}{r^2h}

Recall that:\frac{H}{h} = \frac{R}{r}

So, we have:

\frac{1715}{1080} = \frac{R^2*R}{r^2*r}

\frac{1715}{1080} = \frac{R^3}{r^3}

Take cube roots of both sides

\sqrt[3]{\frac{1715}{1080}} = \frac{R}{r}

Factorize

\sqrt[3]{\frac{343*5}{216*5}} = \frac{R}{r}

\sqrt[3]{\frac{343}{216}} = \frac{R}{r}

\frac{7}{6} = \frac{R}{r}

The curved surface area is calculated as:

Area = \pi rl

Where

l = slant\ height

For the big cone:

A_{big} = \pi RL

For the small cone

A_{small} = \pi rl

Because both cones are similar, then:

\frac{L}{l} = \frac{R}{r}

and

\frac{A_{big}}{A_{small}} = \frac{\pi RL}{\pi rl}

\frac{A_{big}}{A_{small}} = \frac{RL}{rl}

This gives:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{L}{l}

Recall that:

\frac{L}{l} = \frac{R}{r}

So, we have:

\frac{A_{big}}{A_{small}} = \frac{R}{r} * \frac{R}{r}

\frac{A_{big}}{A_{small}} = (\frac{R}{r})^2

Make A_{big} the subject

A_{big} = (\frac{R}{r})^2 * A_{small}

Substitute values for \frac{R}{r} and A_{small}

A_{big} = (\frac{7}{6})^2 * 840

A_{big} = \frac{49}{36} * 840

A_{big} = \frac{49* 840}{36}

A_{big} = 1143.33cm^2

<em>Hence, the curved surface area of the big cone is 1143.33cm^2</em>

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