Answer:
just refresh
Explanation:
you did level up i just checked, it just hasnt updated for you
"A Buffer overflow" vulnerability exploit resulted from the attacker's actions.
Whenever a software or an application writes too much data into a buffer, causing neighboring storage regions to have been corrupted as a consequence, this could be determined as Buffer overflow.
⇒ There are two kinds of Buffer overflow attacks such as:
- <u>Stack-based</u> - It will become more popular to use such memory, as well as that's only available during implementation of any code.
- <u>Heap-based</u> - Those attacks seem to be more difficult to execute because they entail overflowing overall storage capacity allotted for a program further than the space needed for something like the program's present activities.
Thus we can say that the correct answer is a Buffer overflow.
Learn more about Buffer overflow here:
brainly.com/question/4952591
The answer to this question is c
Answer:
u can see the answer in this picture
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
