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2 years ago

5

At 8:00, the temperature was 15 degrees Celsius (°C). Three hours later, the temperature was -15°C. By how many degrees Celsius

did the temperature change?

1 answer:

stepladder [879]2 years ago

5 0

Answer:

30 degrees

Step-by-step explanation:

If you were to draw a number line, 15 and -15 are both 15 units away from 0. So, 15 + 15 =30

Please brainlist!

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A jar contains 17 yellow and 12 green marbles. You randomly draw one marble from the jar then

dexar [7]

Answer:

204/841

Step-by-step explanation:

17/29 times 12/29

3 0

3 years ago

Please help again! Please

Troyanec [42]

1 glass of juice cost $3

1 glass of limonade costs $2

So the proportion between them (Orange) / (juice) = 3/2 or 3¹/₂

6 0

3 years ago

Somebody please assist me in answering this math question.

Sphinxa [80]

Firstly look at the options carefully and we will get to know that two answer options are incorrect because 2 of them are representing AT MOST SIGN which we don't need. So in that way Options B and D are eliminated.

So Now we are left with 2 options A and C. Lets figure it out.
We know that Carlos has 5 complete set with 4 individual figures and josh has 3 complete sets with 14 individual figures.
So lets write in the numerical language:-
let us assume that complete sets are X.
ATQ,
5x + 4 ≥ 3x + 14
subtracting 3x from both sides.
5x -3x + 4 ≥ 14
2x + 4 ≥ 14
subtracting 4 from both sides
2x ≥ 14 - 4
2x ≥ 10
dividing both sides by 2
x ≥ 5 Answer
So correct answer option is C

7 0

3 years ago

Law Incorporation [45]

I'd personally go with A and C, The rest don't make too much sense. Don't count on my answer just yet though.

7 0

3 years ago

Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance

lana66690 [7]

Answer:

Null Hypothesis, $H_0$ : p = 0.20

Alternate Hypothesis, $H_a$ : p > 0.20

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> $H_0$ : p = 0.20

<u>Alternate Hypothesis</u>, $H_a$ : p > 0.20

Here, <u><em>null hypothesis</em></u> states that 20% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of users who develop nausea in a sample of 241 subjects = $\frac{54}{241}$

n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0

3 years ago