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OLga [1]
3 years ago
9

1. classify -6x^5+4x^3+3x^2+11 by degree. 

Mathematics
1 answer:
siniylev [52]3 years ago
3 0

1.

The degree of this polynomial is 5, and because the prefix for 5 is "quin", the answer would be quintic.

2. -2x^2(-5x^2 + 4x^3)

We can use FOIL to simplify this.

10x^4 - 8x^5

Because standard form is decreasing by degree, we need to rearrange the binomial.

The answer is -8x^5 + 10x^4


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Georgianna claims that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.
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Answer:

The  condition  are

           The  Null hypothesis is  H_o  :  \mu = 5

           The  Alternative hypothesis is  H_a  :  \mu <  5

The  check revealed that

             There is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons

Step-by-step explanation:

From the question we are told that

     The  population mean is  \mu =  5 \ year

      The sample size is  n =  20

      The sample mean is  \=  x  =  4.6 \  years

       The  standard deviation is \sigma  =  2.2  \ years

   The  Null hypothesis is  H_o  :  \mu = 5

   The  Alternative hypothesis is  H_a  :  \mu <  5

So i will be making use of  \alpha =  0.05 level of significance to test this claim

    The critical value of  \alpha from the normal distribution table is  Z_\alpha  =  1.645

 

Generally the test statistics is mathematically evaluated as

                 t =  \frac{\= x  - \mu}{ \frac{\sigma }{\sqrt{n} } }

substituting values

                 t =  \frac{ 4.6  - 5}{ \frac{2.2}{\sqrt{20} } }

                t =  -0.8131

Looking at the value of  t and Z_{\alpha } we see that  t <  Z_{\alpha } so we fail to reject the null hypothesis  

  This implies that there is sufficient evidence to support the claim that in a small city renowned for its music school, the average child takes at least 5 years of piano lessons.

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Step-by-step explanation:

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Step-by-step explanation:

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The answer to the question.
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