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3 years ago

Plz help me I forgot How to solve

Mathematics

1 answer:

sveta [45]3 years ago

8 0

Given:

A cyclic quadrilateral and two opposite angles of it in the form of y.

To find:

The value of y.

Solution:

We know that, opposite angles of a cyclic quadrilateral are supplementary angles. So, their sum is $180^\circ$ .

The measures of opposite angles of cyclic quadrilateral are y and 2y. So,

$y+2y=180^\circ$

$3y=180^\circ$

Divide both sides by 3.

$y=\dfrac{180^\circ}{3}$

$y=60^\circ$

Therefore, the value of y is $60^\circ$ .

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Read 2 more answers

Solve the quadratic equation y^2-2y-35=0

soldier1979 [14.2K]

Hello,

To solve we need to factor y^2-2y-35:

(y-7)(y+5)=0

Now solve for :

(When will (y-7)(y+5)equal zero?)

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6 0

3 years ago

If 2x + 5 = 8x, then 12x = ?A.5B.10C.15D.20

butalik [34]

<h2>Answer:</h2> $10.\text{ Option B is correct}$

<h2>Explanation:</h2>

Given the equation expressed as:

$2x+5=8x$

First, we need to calculate the value of "x" from the given expression.

Step 1: Given the equation 2x + 5 = 8x

Step 2: Subtract 5 from both sides:

$\begin{gathered} 2x+5-5=8x-5 \\ 2x+\cancel{5}-\cancel{5}=8x-5 \\ 2x=8x-5 \end{gathered}$

Step 3: Subtract 8x from both sides

$\begin{gathered} 2x-8x=8x-8x-5 \\ -6x=\cancel{8x}-\cancel{8x}-5 \\ -6x=-5 \end{gathered}$

Step 4: Divide both sides by -6

$\begin{gathered} \frac{-6x}{-6}=\frac{-5}{-6} \\ x=\frac{5}{6} \end{gathered}$

Step 5: Get the value of 12x. Substitute x = 5/6 into the expression to have:

$\begin{gathered} 12x=12(\frac{5}{6}) \\ 12x=\cancel{12}^2(\frac{5}{\cancel{6}^1}) \\ 12x=2\times5 \\ 12x=10 \end{gathered}$

Therefore the value of 12x is 10

3 0

1 year ago