How do you convert 10 m/s into m/minute? Use the fact that 60 s = 1 minute to write a coversion factor, and then put that c. factor to use:
60 s = 1 min becomes
60 s
--------
1 min
Now multiply " 10 m/s " by this conversion factor:
10 m/s 60 sec 600 m
----------- * ----------- = ---------------- = 600 m/min (answer)
1 1 min 1 min
Answer: y = x
<u>Step-by-step explanation:</u>
First, find the point where 5x - 2y + 3 and 4x - 3y + 1 intersect using the Elimination Method.
5x - 2y + 3 = 0 → 3(5x - 2y + 3 = 0) → 15x - 6y + 9 = 0
4x - 3y + 1 = 0 → -2(4x - 3y + 1 = 0) → <u> -8x + 6y - 2</u> =<u> 0 </u>
7x + 7 = 0
7x = -7
x = -1
5x - 2y + 3 = 0
5(-1) - 2y + 3 = 0
-5 - 2y + 3 = 0
-2y - 2 = 0
-2y = 2
y = -1
(-1, -1)
Next, find the point where x = y and x = 3y + 4 intersect using the Substitution Method.
x = y
x = 3y + 4 → y = 3y + 4
-2y = 4
y = -2
x = y
x = -2
(-2, -2)
Now, find the line that passes through (-1, -1) and (-2, -2) using the Point-Slope formula. (x₁, y₁) = (-1, -1) and m = 1
y - y₁ = m(x - x₁)
y + 1 = 1(x + 1)
y = x
Answer:
n²+3. is the nth term
Step-by-step explanation:
Answer:
201° and 60°
Step-by-step explanation:
(2)
∠ FHG =
( arc ES + arc FG ), that is
128° =
( 55 + FG ) ← multiply both sides by 2
256° = 55° + FG ( subtract 55° from both sides )
201° = major arc FG
(3)
The measure of the secant- tangent angle FTS is half the difference of the intercepted arcs, that is
∠ T =
( arc FS - arc US )
=
(170 - 50)°
=
× 120°
= 60°