The congruence theorems or postulates that proves the following set of triangles are congruent are:
a. SAS congruence postulate
b. SSS congruence postulate
c. SAS congruence postulate
d. SAS congruence postulate
<h3>Triangle Congruence Postulates or Theorems</h3>
- Two triangles having two pairs of congruent angles and a pair of included sides are congruent by the SAS congruence postulate.
- Two triangles having three pairs of congruent sides are congruent by the SSS congruence postulate.
- Two triangles having two pairs of congruent sides and a pair of included angles are congruent by the SAS congruence postulate.
- Two triangles having two pairs of congruent angles and a non-included side are congruent by the SAS congruence postulate.
Therefore, the congruence theorems or postulates that proves the following set of triangles are congruent are:
a. SAS congruence postulate
b. SSS congruence postulate
c. SAS congruence postulate
d. SAS congruence postulate
Learn more about Triangle Congruence Postulates or Theorems on:
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The answer is B) all real numbers.
This is because no matter what value we plug in for x, it's absolute value will always be positive and therefore greater than -9.
Answer:
The answer is C
Step-by-step explanation:
You solve what is in the parenthesis
then the brackets
then multiply that by 2
then subtracts the 2^3
Its a lot to right down but just know the answer is C
You will use the formula A=lw to find the area. Substitute 2x^3 in for the length and 4x^2 for the width. You would multiply both of these. 2×4 = 8, and x cubed times x squared equals X to the fifth power. You will add the exponents together because the exponent tells you how many times to multiply that value. If there are three x multiplied together (in x cubes) and two x multiplied together(in x squared) that makes five x multiplied together. The answer is represented as A=8x^5. ^ means to the power of.
Answer:
Step-by-step explanation:
For a triangle the area is
If our triangle is isosceles and the 2 congruent sides each measure 4 and they include an angle of 40 degrees, let's say that the vertex angle is 40 and the sides that are not the base each measure 4. If we drop an altitude from the vertex to the base, we cut the triangle into 2 right triangles, with the vertex angle being 20 degrees and the hypotenuse being 4. To find the base, then, which is opposite the angle, we use the sin ratio:
and
4sin(20) = b so
b = 1.368
But we need the whole base, and that is only half of it. So
2b = 2.736
To find the height, which is adjacent to the angle, we use the cos ratio:
and
4cos(20) = h so
h = 3.759
Now we have enough info to find the area of the triangle using the triangle area formula from above:
and
A = 5 meters squared.