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Papessa [141]
3 years ago
11

find the length of the long diagonal of a rhombus when it's area of 24 square centimeters and it's short diagonal is 4 centimete

rs​

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

12

Step-by-step explanation:

A rhombus is a parallelogram with all four sides equal.

Its diagonals are perpendicular.

Each of the triangles formed by the diagonals and the sides are congruent, so the area of the rhombus is 4 times the area of one of the triangles.

Since the short diagonal is given as 4, each of the triangles can be viewed as having a base of 2.  Each triangle's height, h, then is one half the length of the long diagonal.

The are of one of the triangles is 1/2 (base)(height)=(1/2)(2)h

The area of the rhombus is then

4(1/2)(2)h=24

Solving for h gives

h=6

This makes the length of the long diagonal 2h=12

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PLZ HElp!! Solve the inequality. –6 < 2x – 4 < 4
nekit [7.7K]

Answer:

- 1 < x < 4

Step-by-step explanation:

- 6 < 2x - 4 < 4 \\  - 6 + 4 < 2x < 4 + 4 \\  - 2 < 2x < 8 \\  \frac{ - 2}{2}  < x <  \frac{8}{2}  \\  \purple{ \boxed{ \bold{ - 1 < x < 4}}}

6 0
3 years ago
Which of the following statements is likely to be true?
Nostrana [21]

Answer:

c. The interquartile range offers a measure of income inequality among California residents.

Step-by-step explanation:

The range is the midspread which measures statistical dispersion. This is also known as H-spread which is equal to the difference between 75th percentile and 25th percentile. In the given scenario the interquartile range offers measure of income inequality among California residents.

5 0
3 years ago
To qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 an
kolbaska11 [484]

Answer:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

Step-by-step explanation:

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X ~ N (200,20)

For u = 200 and o = 20

For this case we can use the z score in order to solve this problem, given by this formula:

Z = x-u/o

For this part we want to find a value a, such that we satisfy this condition:

P (X > a) = 0.1 (a)

P (X < a) = 0.9 (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P ( X < a) = P (X-u/o < a - u/o) = 0.9

P (z < a-u/o) = 0.9

But we know which value of z satisfy the previous equation so then we can do this:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

3 0
2 years ago
|1/2b-8|=|1/4b-1|<br> b=____ and ____
Deffense [45]

Answer:

  b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

  1/2b -8 = 0

  b -16 = 0

  b = 16

The absolute value function on the right has a turning point where its value is zero:

  1/4b -1 = 0

  b -4 = 0

  b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

  1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

  -(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

  -(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

  1/2b -8 = 1/4b -1

  2b -32 = b -4 . . . . . . . . multiply by 4

  b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

  -(1/2b -8) = 1/4b -1 . . . . equation in this domain

  -2b +32 = b -4 . . . . . . multiply by 4

  36 = 3b . . . . . . . . . . . add 2b+4 to both sides

  12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

  b = 12  and  b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

  g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}

Then the solutions are the values of b that make g(b) = 0.

4 0
2 years ago
Brody added a fraction to 5/6 to get 31/30. Use the equation a/b + c/d = (ad +bc)/ bd to find the fraction he added
sashaice [31]
The fraction he added is 6/30, or 1/5.
I'm not 100% sure about the equation you want me to use but I did the work this way:

5/6+x/30=31/30 (the denominator has to equal 30 because you are adding. You need a common denominator which is why you need to change 5/6. We can label the numerator as a hidden value x)

25/30+x=31/30

You can then work backwards and basically subtract 25 from 31 and get 6; so x=6

8 0
3 years ago
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