

- <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
- <u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
- <u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>


<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>


<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>



<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>


<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>



<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>


<u>Now</u><u>, </u>









Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .
Answer:
(1,1) (2,2) (1,2) (1,5) (4,4) (4,5)
there are a lot more but those are some.
Step-by-step explanation:
Answer: -1 and 5.
Step-by-step explanation:
x - 4x = 5 : Move the constant to the left.
x^2 - 4x - 5 = 0 : Rewrite the expression.
x^2 + x - 5x - 5 = 0 : Factor the expressions.
x(x+1) - 5(x+1) = 0 : Factor the expression.
(x+1)(x-5) = 0 : Seperate into possible cases.
x + 1 = 0, x - 5 = 0 : Solve the equations.
x = -1, x = 5 : The equation has 2 solutions.

we can rewrite it as

we can see that 1/4 is in multiple in both terms
so, we can factor it out
so, we get
..............Answer
Answer:
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