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rodikova [14]
3 years ago
12

In right triangle ΔABC, ∠C is a right angle, AC = 20 and m∠A = 41º. Find AB to the nearest tenth.

Mathematics
2 answers:
Rom4ik [11]3 years ago
6 0

<u>Answer:</u>

<h2>AB = 26.5</h2>

<u>Explanation:</u>

ΔABC is right in the angle ∠C

in this case AB is the hypotenuse of the triangle ABC

according to the given data we will use the <u>length</u> of AC which is the adjacent side to the angle ∠A and the <u>Cosine</u> of the angle ∠A in the following formula:

the hypothenuse = adjacent side / cosine of the angle

AB = 20 / cos(41°)

AB = 26.5

kykrilka [37]3 years ago
4 0

Answer:

AB = 26.5º

Step-by-step explanation:

cosA = adj/hyp

cosA = AC/AB

cos41 = 20/AB

Multiply both sides by AB

AB * cos41 = 20

Divide both sides by cos41

AB = 20/cos41

AB = 26.5º

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