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prisoha [69]
3 years ago
15

Plz help! Thank you so much!

Mathematics
1 answer:
Sergio [31]3 years ago
3 0

Answer:

I dont have idea what I need to the to help you

Step-by-step explanation:

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11. How many different ways can the 16 numbered pool balls be placed in a line on the pool table?
nikklg [1K]

Answer:

The number of ways are 16! or 20,922,789,888,000.

Step-by-step explanation:

Consider the provided information.

We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.

For the first place we have 16 balls.

For the second place we have 15 balls left.

Similarly for the third place we have 14 balls as two balls are already arranged and so on.

Or we can say that this is the permutation of 16 things taking 16 at a time.

Thus the number of ways are: 16! or  ^{16}P_{16}

16!=16\times15\times14\times13......\times2\times1=20,922,789,888,000

Hence, the number of ways are 16! or 20,922,789,888,000.

7 0
3 years ago
Alex went bowling. He managed to get 3 strikes after 15 attempts. If you were to
algol13

Answer:

Theoretical Probability because its what should happen but experimental is what happens

Step-by-step explanation:

5 0
3 years ago
Please can someone helpppp
GenaCL600 [577]
A) 8 - add up the how many numbers there are after the 4 on the left column

b) 41 - line up all of the numbers from least to greatest and find the middle number

c) 39 - do step b again but this time remove the oldest worker and add the younger one in
6 0
3 years ago
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Each Purse Contains 8 Coins. Find A rule to give the total number of coins in 'n' purses.
kozerog [31]

Answer:

8n

Step-by-step explanation:

8 0
3 years ago
To earn an A in an algebra course, a student must have a test average of at least 90. Mary has grades of 95, 82, 88 on her first
Fofino [41]

Answer: Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

Step-by-step explanation:

Let x be the grades scored by Mary in the fourth algebra test.

Mary has grades of 95, 82, 88 on her first three algebra tests.

Then, the combined scores in four test will become = 95+82+88+x =  265+x

Average score = (Sum of all scores) ÷ (Number of tests)

=\dfrac{265+x}{4}

As per given ,

To earn an A in an algebra course, a student must have a test average of at least 90.

i.e. Average score ≥ 90

\Rightarrow\ \dfrac{265+x}{4}\geq90\\\\\Rightarrow\ 265+x\geq 90\times4=360\\\\\Rightarrow\ x\geq360-265 =95\\\\\Rightarrow\ x\geq90

Hence, Mary need to make at-least 95 on her fourth test to earn an A in her algebra course.

5 0
3 years ago
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