Answer:
0.14
Step-by-step explanation:
1/7 = 0.142
Since 2<5 the answer is 0.14.
You can see that angle TQV = 90 degrees
Angle RQV = 136 degrees
Angles RQV and UQV are supplementary and equal 180 degrees since they form a straight line. Therefore angle UQV = 180 - 136 = 44 degrees.
TQU + UQV = 90 degrees. Therefore, TQU = 90 - UQV.
90 - 44 = 46 degrees for angle TQU.
I feel like it’s B but I’m not sure
Use the law of sines....(sina/A=sinb/B=sinc/C for any triangle)
What that means is the sine of an angle divided by the length of the side opposite the angle is a ratio that is true each angle/side pair...In this case:
sin90/122=sinc/22 rearrange to solve for sinc
sinc=(22sin90)/122 now take the arcsin to solve for c
c=arcsin[(22sin90)/122]
c≈10.388857815469611987441020361405
c≈10.39° (to nearest hundredth of a degree)
Step 1:
Calculate the measure of angle ∠ABC
From the triangle in the question,
Step 2:
Calculate the value of AB using the cosine rule below
By substituting the values, we will have
![\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Da%5E2%2Bc%5E2-2%5Ctimes%20a%5Ctimes%20c%5Ctimes%5Ccos%20B%20%5C%5C%20b%5E2%3D10%5E2%2B15%5E2-2%5Ctimes10%5Ctimes15%5Ctimes%5Ccos%20115%5E0%20%5C%5C%20b%5E2%3D100%2B225-300%5Ctimes%28-0.4226%29%20%5C%5C%20b%5E2%3D325%2B126.78%20%5C%5C%20b%5E2%3D451.78%20%5C%5C%20%5Ctext%7BSquare%20root%20both%20sides%7D%20%5C%5C%20%5Csqrt%5B%5D%7Bb%5E2%7D%3D%5Csqrt%5B%5D%7B451.78%7D%20%5C%5C%20b%3D21.26%5Coperatorname%7Bkm%7D%20%5Cend%7Bgathered%7D)
Hence,
The distance of point A to point C is = 21.26km
