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BabaBlast [244]

3 years ago

10

The reciprocal of a fraction must be found to solve the problem. What is the reciprocal fraction that is required?

2 answers:

Scilla [17]3 years ago

7 0

Answer:

6/31

Explanation:

First, you need to turn them into improper fractions. Then, you flip the second one. 5 1/6 as an improper fraction is 31/6, and the reciprocal is 6/31.

kolezko [41]3 years ago

3 0

6/31 is the answer for your question.

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What distance was used to define the astronomical unit (AU)

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Use linear regression to find the equation for the linear function that best fits this data. Round both numbers to two decimal p

natta225 [31]

Answer:

The equation of the linear function that best fits the data is,

<em>y</em> = 18.66<em>x</em> + 66.87.

Step-by-step explanation:

The line of best is of the form: <em>y</em> = <em>mx</em> + <em>b</em>.

Here, <em>m</em> = slope of the line and <em>b</em> = intercept.

The formula to compute the intercept and slope are:

$b=\frac{\sum Y.\sum X^{2}-\sum X.\sum XY}{n.\sum X^{2}-(\sum X)^{2}}$

$m=\frac{n.\sum XY-\sum X.\sum Y}{n.\sum X^{2}-(\sum X)^{2}}$

Consider the table below for the values of <em>∑ X, ∑ Y, ∑ X² </em>and <em>∑ XY</em>.

Compute the value of intercept and slope as follows:

$b=\frac{\sum Y.\sum X^{2}-\sum X.\sum XY}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(793\times91)-(21\times3102)}{(6\times91)-(21)^{2}} =66.867$

$m=\frac{n.\sum XY-\sum X.\sum Y}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(6\times3102)-(21\times793)}{(6\times91)- (21)^{2}} =18.657$

The line of best fit is:

$y=mx+b\\y=18.657x+66.867\\y=18.66x+66.87$

Thus, the equation of the linear function that best fits the data is <em>y</em> = 18.66<em>x</em> + 66.87.

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3 years ago

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scoundrel [369]

Answer:

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Step-by-step explanation:

4 + negative 2 (or -2) = 2

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