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3 years ago

Find the diffrence between temperature -30 degrees c and 70 degrees c?

Mathematics

2 answers:

kati45 [8]3 years ago

6 0

One is very cold below freezing and one is just cold hope this helps

andreyandreev [35.5K]3 years ago

4 0

One is colder than the other.
Hope this helps :)

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Complete the equation of variation where y varies inversely as x and y = 0.125 when x = 8.

patriot [66]

Complete the equation of variation where y varies inversely as x and y = 0.125
when x=8

3 0

3 years ago

Giá trị x thoả mãn x(x − 3) + x − 3 =0 là

svet-max [94.6K]

Here we will use the trial and error method.

We will try putting different values of x.

$\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}$

<h2>Again,</h2><h3>x=3</h3>

$\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}$

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>

5 0

3 years ago

Whats the sum of the polynomials (2x3 − 5x − 1) + (4x3 + 8x + 3)

Ipatiy [6.2K]

Answer: 23x

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find x so that the points (x,x+1), (x+2,x+3) and (x+3,2x+4) form a right-angled triangle.

azamat

Let a, b, and c be vectors each starting at the origin and terminating at the points (x, x + 1), (x + 2, x + 3), and (x + 3, 2x + 4), respectively.

Then the vectors a - b, a - c, and b - c are vectors that point in directions parallel to each of the legs formed by the triangle with these points as its vertices.

If this triangle is to contain a right angle, then exactly one of these pairs of vectors must be orthogonal. In other words, one of the following must be true:

(a - b) • (a - c) = 0

or

(a - b) • (b - c) = 0

or

(a - c) • (b - c) = 0

We have

a - b = (x, x + 1) - (x + 2, x + 3) = (-2, -2)

a - c = (x, x + 1) - (x + 3, 2x + 4) = (-3, -x - 3)

b - c = (x + 2, x + 3) - (x + 3, 2x + 4) = (-1, -x - 1)

Case 1: If (a - b) • (a - c) = 0, then

(-2, -2) • (-3, -x - 3) = (-2)×(-3) + (-2)×(-x - 3) = 2x + 12 = 0 ==> x = -6

which would make a - c = (-3, 3) and b - c = (-1, 5), and their dot product is not zero. Then the triangles vertices are at the points (-6, -5), (-4, -3), and (-3, -8).

Case 2: If (a - b) • (b - c) = 0, then

(-2, -2) • (-1, -x - 1) = (-2)×(-1) + (-2)×(-x - 1) = 2x + 4 = 0 ==> x = -2

which would make a - c = (-3, -1) and b = (-1, 1), and their dot product is also not zero. The vertices are the points (-2, -1), (0, 1), and (1, 0).

Case 3: If (a - c) • (b - c) = 0, then

(-3, -x - 3) • (-1, -x - 1) = (-3)×(-1) + (-x - 3)×(-x - 1) = x ² + 4x + 6 = 0

but the solutions to x here are non-real, so we throw out this case.

So there are two possible values of x that make a right triangle, x = -6 and x = -2.

3 0

3 years ago

6x square +11x-10 Factories

vova2212 [387]

Answer:

(2x+5)(3x-2)

Step-by-step explanation:

6x²+11x-10

6x²+15x-4x-10

3x(2x+5)-2(2x+5)

(2x+5)(3x-2)

7 0

3 years ago