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lozanna [386]
3 years ago
10

A = 16, b = 20, mZ B = 40 Law of cosines

Mathematics
1 answer:
bezimeni [28]3 years ago
4 0
What is this ?chfufuykygiufffjfufuf
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What is the domain of this table X 1 2 3 4 Y 2 4 3 2
Hoochie [10]
1,2,3,4 are the domain. The x column is always the domain.
3 0
4 years ago
HELP ASAP PLEASE
Serga [27]

Answer:

Step-by-step explanation:

The bases of a triangular prism are equilateral triangles, since they have equal sides: 5, 5, and 5

yes, since if all lateral faces are rectangles, rectangles are formed from 4 perpendicular segments, thus, if all edges of the lateral faces are perpendicular, then they are rectangles

6 0
3 years ago
Explain how proving to triangles congruent can help prove parts of the triangle congruent.
nydimaria [60]

Answer:

CPCTC - Corresponding Parts of Congruent Triangles are Congruent

Step-by-step explanation:

When two triangles are congruent, this means they have the same shape and the same size. To have the same shape, each angle must be congruent. To have the same size, each side length must be congruent. When you know two triangles are congruent you can say each corresponding part of congruent triangles is congruent. This is known as CPCTC.

7 0
3 years ago
I have to transfer this graph into a vertex form equation, but I'm not sure how to.​
tino4ka555 [31]

Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

Step-by-step explanation:

vertex form is y=a(x-h)^2 + k

here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.

so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.

now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have

-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a

the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2

8 0
2 years ago
Find limit as x approaches -3- of x/(sqrt(x^2-9)
gregori [183]
lim_{x \rightarrow -3} \frac{x}{x^2-9} =lim_{x \rightarrow -3} \frac{1}{2x} = \frac{1}{2(-3)} =- \frac{1}{6}
5 0
4 years ago
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