G(x) = 3x² - 5x + 7
b) g(-2) ==> Substitude -2 into x
g(-2) = 3(-2)² - 5(-2) + 7
g(-2) = 12 + 10 + 7
g(-2) = 29
c) g(4) ==> Substitude 4 into x
g(4) = 3(4)² - 5(4) + 7
g(4) = 48 - 20 + 7
g(4) = 35
d) g(-x) ==> Substitude -x into x
g(-x) = 3(-x)² - 5(-x) + 7
g(-x) = -3x² + 5x + 7
e) g(1 - t) ==> Substitude 1 - t into x
g(1 - t) = 3(1 - t)² - 5(1 - t) + 7
g(1 - t) = 3(1 - 2t + t²) - 5 + 5t + 7
g(1 - t) = 3 - 6t + 3t² - 5 + 5t + 7
g(1 - t) = 3t² - t + 5
Consider the vertices of parallelogram JKLM with vertices J(2,2) , K(5,3) , L(5,-3) and M(2,-4).
Perimeter JKLM = Length JK + Length KL + Length LM + Length JM
Length JK = (2,2) (5,3)
The length(or distance) between two points say
and
is given by the distance formula:

Now, length JK = 
=
units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, LM =
units
Now, length KL = 
= 6 units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, JM = 6 units
Perimeter of JKLM =
+
+ 6 + 6
= 2
+ 12
= 18.324
Rounding to the nearest tenth, we get
= 18.3 units.
Therefore, the perimeter of JKLM is 18.3 units.
Answer:
x= -40
Step-by-step explanation:
Cost
C(x)=1,600+20x
P(x)=100-x
Revenue=x*p(x)
=x*(100-x)
=100x-x^2
Cost=Revenue
1600+20x=100x-x^2
1600+20x-100x+x^2=0
1600-80x+x^2=0
Solve using quadratic formula
Formula where
a = 1, b = 80, and c = 1600
x=−b±√b2−4ac/2a
x=−80±√80^2−4(1)(1600) / 2(1)
x=−80±√6400−6400 / 2
x=−80±√0 / 2
The discriminant b^2−4ac=0
so, there is one real root.
x= −80/2
x= -40
All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35