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melomori [17]
3 years ago
11

Which symbol could be written in both circles in order to

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0

 ≥ can be written in both the circles

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What's 1+1? <br><br>Brainliest With The Correct Answer​
GrogVix [38]

2 is the answer.........

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2 years ago
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Use the given similar triangles to find the value of x<br> I need the answer fast please!!
Yuki888 [10]

Answer:

I believe the answer is x=7

Step-by-step explanation:

<em>3x</em> and<em> 4x-1 </em> are corresponding sides and so are <em>14</em> and <em>18</em>.

You cross multiply with the smaller triangle lengths at the top.

3x/(4x-1)= 14/18

Cross multiply to get

18(3x)= 14(4x-1)

54x=56x-14

Subtract 54x on the other side and add 14 to the other (or subtract 56x to the other side)

you get 14=2x and divide 14 by 2 to get x=7

8 0
3 years ago
A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is
MAXImum [283]

The answer is 0.04 (I hope). Here is an explanation:

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3 years ago
In the decimal number 532.987, how many times greater is the place value of the digit 9 than the place value of the digit 7
MakcuM [25]

It would be 100 times greater.

7 0
3 years ago
Expand (2x -3y)^5 using the given formula.
horrorfan [7]
(2x-3y)^5

(2x-3y)(2x-3y)(2x-3y)(2x-3y)(2x-3y)

1st and 2nd power :
(2x-3y)(2x-3y) = 2x(2x-3y)-3y(2x-3y) = 4x² - 6xy - 6xy + 9y²
= 4x² - 12xy + 9y²

3rd power:
(2x-3y)(4x² - 12xy + 9y²) = 2x(4x² - 12xy + 9y²) - 3y(4x² - 12xy + 9y²)
8x³ - 24x²y + 18xy² - 12x²y +36xy² - 27y³
8x³ - 24x²y - 12x²y + 18xy² + 36xy² - 27y³
8x³ - 36x²y + 54xy² - 27y³

4th power
(2x-3y)(8x³ - 36x²y + 54xy² - 27y³) = 2x(8x³ - 36x²y + 54xy² - 27y³) -3y(8x³ - 36x²y + 54xy² - 27y³) = 16x^4 - 72x³y + 108x²y² - 54xy³ - 24x³y + 108x²y² - 162xy³ + 81y^4
16x^4 - 72x³y - 24x³y + 108x²y² + 108x²y² - 54xy³ - 162xy³ + 81y^4
16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4

5th power
(2x-3y)(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
2x(</span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4) - 3y(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
= 32x^5 - 192x^4y + 432x</span>³y² - 432x²y³ + 162xy^4 - 48x^4y + 288x³y² - 648x²y³ + 648xy^4 - 243y^5

32x^5 - 192x^4y -48x^4y + 432x³y² + 288x³y² - 432x²y³ - 648x²y³ + 162xy^4 + 648xy^4 - 243y^5

32x^5 - 240x^4y + 720x³y² - 1,080x²y³ + 810xy^4 - 243y^5
3 0
3 years ago
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