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tigry1 [53]
2 years ago
14

Explain three tests that uses for tests normality​

Computers and Technology
2 answers:
Volgvan2 years ago
7 0

Answer:

<h2>Methods used for test of normality of data. ... [10] There are various methods available to test the normality of the continuous data, out of them, most popular methods are Shapiro–Wilk test, Kolmogorov–Smirnov test, skewness, kurtosis, histogram, box plot, P–P Plot, Q–Q Plot, and mean with SD.</h2>

Explanation:

<h2>HOPE IT HELPS YOU</h2>
Ira Lisetskai [31]2 years ago
4 0

Answer:

123

Explanation:

it's very hard how can you know

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In poor weather , you should ___ your following distance.
svlad2 [7]

Answer:

lengthen

Explanation:

will take more time to stop on wet and slippery surfaces

3 0
3 years ago
What is virtual reality?
Burka [1]
The computer-generated simulation of a three-dimensional image or environment that can be interacted with in a seemingly real or physical way by a person using special electronic equipment, such as a helmet with a screen inside or gloves fitted with sensors.
4 0
3 years ago
On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of f0 * rn, where n is the distance
Stels [109]

Answer:

#include <stdio.h>

int main()

{

float your_value1, your_value2, your_value3, your_value4, your_value5;

printf("Enter a frequency: ");

scanf_s("%f", &your_value1);//storing initial key frequency in your value 1

 

float r = 2.0 / 12;//typing 2.0 so it is treated as float and not int

your_value2 = your_value1 * r * 1; //initial*r*n

your_value3 = your_value1 * r * 2; //initial*r*n

your_value4 = your_value1 * r * 3; //initial*r*n

your_value5 = your_value1 * r * 4; //initial*r*n

printf("%0.2f %0.2f %0.2f %0.2f %0.2f", your_value1, your_value2, your_value3, your_value4, your_value5);

return 0;

}

Explanation:

The purpose of this exercise is to make you understand the difference between float and int. float variables are used when you need decimals in your calculations. int is used when you need integers. The problem in this exercise was the formulation of r. Now r is = 2/12, this means that when we type r as that, the computer assumes that it is an integer and treats it as such. So, it will convert the 0.166667 into 0. To overcome this, all you have to do is type 2.0 instead of 2 alone.

The %0.2 command restricts the float variable to 2 decimal places. By default, it has 6 decimal places.

I have used the function scanf_s instead of scanf simply because my compiler does not work with scanf.

3 0
3 years ago
Which frequency will 802.11n work on if on a single-link network?
Allushta [10]

802.11n can function in "mixed mode" on the 2.4 GHz frequency, with a theoretical maximum speed of 300 Mbps, or on the 5 GHz frequency.

<h3>What do you mean by frequency?</h3>

In the case of electrical current, frequency is the number of times a sine wave repeats or completes, a positive-to-negative cycle.

802.11n can operate in "mixed mode" on the 2.4 GHz frequency, which will support just 802.11b or 802.11g-capable systems but will slow the entire network down to the maximum speed of the earliest standard connected, at a theoretical maximum speed of 300 Mbps.

Learn more about the single-link network:

brainly.com/question/4272298

#SPJ1

8 0
1 year ago
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

   int k, n, total;

   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

       total = total + ( k * k * k );

       // value of k is incremented to go to the next number

k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0
3 years ago
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