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34kurt
3 years ago
6

A basketball court is a rectangle that is 94 ft long.The area is 4700 square feet.What is the width of a basketball court?

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0
A= l×w 4700=94×? 4700÷94=50 ~jz Hope it helps
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A sequence is defined by an = -5+ (n - 1) 14, where n is a positive integer. What is the value of 410?
Jobisdone [24]

The sequence an = -5 + (n - 1)14 is an arithmetic sequence

The value of a10 is 121

<h3>How to determine the the a10-th term?</h3>

The sequence is given as:

an = -5 + (n - 1)14

To calculate the value of a10, we set n = 10

So, we have:

a10 = -5 + (10 - 1) * 14

Evaluate the difference

a10 = -5 + 9 * 14

Evaluate the product

a10 = -5 + 126

Evaluate the sum

a10 = 121

Hence, the value of a10 is 121

Read more about sequence at:

brainly.com/question/6561461

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2 years ago
Carl filed a claim after he rear-ended another car, causing damage to each
aksik [14]

Answer:COLLISION

Step-by-step explanation:

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4 years ago
96 is 44 percent of what? Step by step
Elena-2011 [213]

Answer:

218.18

Step-by-step explanation:

To find what number 96 is 44% of is we can use the formula:

\frac{part}{whole} =\frac{percent}{100}

Just substitute 94 and 44 into the equation:

\frac{96}{x} =\frac{44}{100}

9600=44x\\218.1818...

Or rounded,

218.18

4 0
3 years ago
Determine the values of the unlabeled parts of the triangle.
____ [38]

Answer:

∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

90 + 26.6 + ∠Q = 180

∠Q + 116.6 = 180

∠Q = 180 - 116

∠Q = 63.4°

We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ  :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47

4 0
3 years ago
What is the equation of a line that passes through the point (1. 8) and is perpendicuarto rene rose cons y=+32 Enter your answer
Alina [70]

Answer:

-12yx

Step-by-step explanation:

y=x/2+3

y-3= -6

-6y= x/2

-6 x 2= -12yx

8 0
3 years ago
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