A sequence is defined by an = -5+ (n - 1) 14, where n is a positive integer. What is the value of 410?

1 answer:

7 0

The sequence an = -5 + (n - 1)14 is an arithmetic sequence

The value of a10 is 121

<h3>How to determine the the a10-th term?</h3>

The sequence is given as:

an = -5 + (n - 1)14

To calculate the value of a10, we set n = 10

So, we have:

a10 = -5 + (10 - 1) * 14

Evaluate the difference

a10 = -5 + 9 * 14

Evaluate the product

a10 = -5 + 126

Evaluate the sum

a10 = 121

Hence, the value of a10 is 121

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Rainbow [258]

Answer:

$y=-4x+2$

Step-by-step explanation:

First we find the slope of the line AB passing through the point (2,0)
line AB is perpendicular to the line $y=\frac{1}{4}x-3$ , this equation is slope intercept for, which is $y=mx+b$ so our m or slope is $\frac{1}{4}$
Since the slope of line AB is perpendicular to $m=\frac{1}{4}$ then we use the equation $slope of line1\times slopeofline2=-1$ , so what do we multiply $\frac{1}{4}$ by to get -1? -4 right, so that's the slope of line AB with the point (2,0)
Now line CD is parallel to line AB, that means it has the same slope as AB, so slope of CD is -4
So we make the equation $y-y_1=m(x-x_1)$ so m= -4 and our point is (-1,6)
$y-(6)=-4(x-(-1)\\y-6=-4x-4\\y=-4x-4+6\\y=-4x+2$ thats the equation of line side CD