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Lemur [1.5K]
3 years ago
9

Show ur work idc if ur answer is wrong but i need to copy work

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0
Gxgdhehshwhshwhebhsjshebdhdhebdhdhebehshejejej
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If j= 14, find the value of 1/2j.
Yakvenalex [24]

Answer:7

Step-by-step explanation:

1/2 of j is the same as j ÷ 2

14 ÷ 2 = 7

8 0
3 years ago
Write the following number in standard decimal form four tenths
Crazy boy [7]
0.4 is four tenths. 0.4 = 4/10=2/5
8 0
3 years ago
Read 2 more answers
What is the answer to (−t/3)^2?
Sloan [31]

Answer:

Simplify the expression.

t^/9

Step-by-step explanation:

7 0
3 years ago
Brainly annie has 2 bags of apples and 5 single apples eva has 1 bag of apples and 11 single apples they have the same amount of
bekas [8.4K]

Answer:

34 apples

Step-by-step explanation:

To answer: try setting up each of the equations for Annie and Eva.

Annie: 2(bag) + 5

Eva: 1(bag) + 11

Those two equations equal each other. So set that up:

2(bag) + 5 = 1(bag) + 11

Now solve for the size of the bag.

2(bag) - 1(bag) = 11 - 5

1(bag) = 6 apples

Now substitute 6 back into either equation to determine number of apples.

Annie: 2(6) + 5 = 12+5=17

They each have 17, so there are 34 apples in total.

5 0
3 years ago
) find a vector parallel to the line of intersection of the planes 5x − y − 6z = 0 and x + y + z = 1.
snow_tiger [21]
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.

Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>

We calculate the cross product as a determinant of (i,j,k) and the normal products

    i   j   k
   5 -1 -6
   1  1  1

=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>

Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0

Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
5 0
3 years ago
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