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White raven [17]
2 years ago
13

Solv the following inequality. p – 4 < -11

Mathematics
1 answer:
bogdanovich [222]2 years ago
6 0

Answer:

p < -7

Step-by-step explanation:

.................

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A lumber yard has scrap wood for sale. One employee recorded the measurements for the lengths of 50 different wood boards. The m
marusya05 [52]

Answer:

The updated IQR is 14.54.

Step-by-step explanation:

The interquartile range is given by the difference between the 75th percentile(value that is greater than 75% of the measures) and the 25th percentile.

This means that each piece of wood is actually 5 inches shorter than the value recorded by the employee.

This means that the length of each wood is less than 5. However, the difference between the 75th percentile and the 25th percentile will stay the same, since both were subtracted by 5.

The updated IQR is 14.54.

5 0
2 years ago
How do I find the value of -72÷(-9)
galben [10]
Just divide regular and the answer will be positive. the answer will be 8

remember:
two positives = positive
two negatives = positive
one positive, one negative = negative
7 0
2 years ago
Find the degree of this polynomial. –s5 − 4s3 + 4s2 + 5s
mestny [16]

Answer:

Can you picture the question?

6 0
3 years ago
Help with this question, please!
jonny [76]

Answer:

The last choice is the one you want.

Step-by-step explanation:

Simply take the x coordinate and subtract 4, then do the same with the y coordinate since the vector movement is <-4, -4>.  The first coordinate F is <4,0>.  Subtract 4 from both of those coordinates and end up at <0, -4>.  The second coordinate G is <1, 3>.  Subtract 4 from both of those and end up at <-3, -1>.  The third coordinate H is <2, 6>.  Subtract 4 from both of those and end up at <-2, 2>.  The last coordinate I is <4, 2>.  Subtract 4 from both of those and end up at <0, -2>.  

6 0
3 years ago
X over 85 = 72 over 100
Basile [38]

Answer:

x/85=72/100

2 can devide 7 and 100

x/85=18/25

cross multiply

25×x=18×85

25×=1530

×=306/5

×=61.2

5 0
3 years ago
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