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2 years ago

Find the x coordinate of the vertex of the parabola sketched in the figure below ?

Mathematics

1 answer:

ivanzaharov [21]2 years ago

5 0

Answer:

Step-by-step explanation:

x-coordinate of vertex is 4

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The law of Cosines Is......

iogann1982 [59]

Answer: $\Large\boxed{C.~21}$

Step-by-step explanation:

The goal of the question

Find the value of 2abcosC

Given information

a = 4

b = 3

c = 2

Given formula (Law of Cosine)

$c^2=a^2+b^2-2abcosC$

Substitute values into the formula (Leave 2abcosC as it is)

$(2)^2=(4)^2+(3)^2-2abcosC$

Simplify the exponents

$4=16+9-2abcosC$

Simplify by addition

$4=25-2abcosC$

Add 2abcosC on both sides

$4+2abcosC=25-2abcosC+2abcosC$

$4+2abcosC=25$

Subtract 4 on both sides

$4 + 2abcosC-4=25-4$

$\Large\boxed{2abcosC=21}$

Hope this helps!! :)

Please let me know if you have any questions

5 0

1 year ago

Read 2 more answers

Instructions:Select the correct answer from the drop-down menu. Dave is helping his grandmother make trail mix. His grandmother

Mazyrski [523]

Set up a proportional relationship:

xf/1n=(f/5)/(n/3)

xf/1n=3f/(5n) multiply both sides by 1n

xf=3f/5 so

x=3/5

Dave must mix in 3/5 of a cup of fruit with a single cup of nuts.

You could of also just noted that you need to multiply 1/5 times 3 because 1/5 mixes with just 1/3 of a cup of nuts...

8 0

3 years ago

Please help me with this!

salantis [7]

The original area of a face would be a^2. Now that you added b to the edge, the new area of each face would be (a+b)^2. To find how much the are increased, subtract a^2 from (a+b)^2. $(a+b)^2-(a^2)= a^2+2ab+b^2-(a^2)= 2ab+b^2= b(2a+b)$ So the answer is b(2a+b)