with the equation of the slope for two points given, m=Y2-Y1/ X2-X1, you can obtain the slope , x1= 3, y1 = -1 , x2= -1, y2= 2
m = 2-(-1)/ -1-3 ⇒ m= 3/-4, m = -3/4, therefore the slope is - 3/4
The final probability is the weighted average of the playing probabilities calculated over the possible weather options:
P(john practices cello; given that it rains) * P(it rains) +
P(john practices cello; given that it does not rain) * P(it does not rain) =
0.6 * 0.7 + 0.4 * 0.3 = 0.54
The probability is 54%
Answer:
i think N=32
Step-by-step explanation:
The probability that a part picked from this batch at random is either red or L-shaped is 0.68
Step-by-step explanation:
Let us revise some rules of probability
The addition rules are:
- P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen at the same time)
- P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they have at least one outcome in common)
∵ A batch has 100 parts
∵ 40 are red
- Probability of an event is the [even occurs/total outcomes]
∴ P(red) = 
∵ 50 are L-shaped
∴ P(L-shaped) = 
∵ 22 are both red and L-shaped
∴ P(red and L-shaped) = 
This is non-mutually exclusive because there is a common between them, so we will use the 2nd rule
∵ P(red or L-shaped) = P(red) + P(L-shaped) - P(red and L-shaped)
∴ P(red or L-shaped) = 0.4 + 0.5 - 0.22
∴ P(red or L-shaped) = 0.68
The probability that a part picked from this batch at random is either red or L-shaped is 0.68
Learn more:
You can learn more about the probability in brainly.com/question/2254182
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<em>Hey </em><em>mate!</em><em>!</em>
<em>Answer:</em>
<em>n(</em><em>A)</em><em>=</em><em>1</em><em>2</em>
<em>Solution</em><em>,</em>
<em>A=</em><em>{</em><em>3</em><em>,</em><em>6</em><em>,</em><em>9</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>8</em><em>,</em><em>2</em><em>1</em><em>,</em><em>2</em><em>4</em><em>,</em><em>2</em><em>7</em><em>,</em><em>3</em><em>0</em><em>,</em><em>3</em><em>3</em><em>,</em><em>3</em><em>6</em><em>}</em>
<em>Just </em><em>count </em><em>the </em><em>elements</em><em>,</em>
<em>There </em><em>are </em><em>1</em><em>2</em><em> </em><em>elements </em><em>in </em><em>the </em><em>set.</em>
<em>So </em><em>the </em><em>cardinal </em><em>number </em><em>of </em><em>the </em><em>set </em><em>is </em><em>1</em><em>2</em><em>.</em>
<h2>
<em>Hope </em><em>it </em><em>helps.</em><em>.</em><em>.</em></h2>