Answer:
c. 0.1151
Step-by-step explanation:
d) the probability that, on average, fish are larger than 86 centimeters in length.The area under part of a normal probability curve is directly proportional to probability and the value is calculated as
z = (x₁−x) /σ
where z = propability of normal curve
x₁ = variate mean = 86cm
x = mean of 80cm
σ = standard deviation = 5cm
applying the formula,
z= (86-80)/5
z = 6/5 =1.2
Using a table of partial areas beneath the standardized normal curve (see Table of normal curve, a z-value of 1.2 corresponds to an area of 0.3849 between the mean value. but, because the standard curve has 0.5, then will minus 0.3849 from 0.5= 0.5 - 0.3849 = 0.1151
Thus the probability of a fish are larger than 86 centimeters in length is 0.1151
A. 32500
b. 60,400
c. 2.4 x 10 ^ -6
d. 1.47 x 10 ^3
Step-by-step explanation:
∆=3*6=18
[]=5*15=75
75+18=93 in squared
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
