Question

What is the factorization of 121b4 − 49? (11b − 7)(11b − 7) (11b 7)(11b − 7) (11b2 − 7)(11b2 − 7) (11b2 7)(11b2 − 7)

Answer 1

The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).

The equation 121b⁴ − 49

To find the Factorization of 121b⁴ − 49.

What is the factor of a^2-b^2?

The factor of a^2-b^2 is  (a+b)(a-b)

We have write the given equation in the form of a^2-b^2

$= 121b^4 - 49\\= (11b^2)^2 - 7^2\\= (11b^2 + 7)(11b^2 - 7)$

Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).

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