What is the factorization of 121b4 − 49? (11b − 7)(11b − 7) (11b 7)(11b − 7) (11b2 − 7)(11b2 − 7) (11b2 7)(11b2 − 7)
1 answer:
The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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