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Margarita [4]
3 years ago
15

Agustin Mateo and I tomorrow I'll training baseball cards Augustine has one fourth as many cars as Mateo Mateo have 1/2 as many

cars as tomorrow who has more cards
Mathematics
1 answer:
Finger [1]3 years ago
7 0

Answer:

Tomorrow has the most cards followed by Mateo, then Agustin

Step-by-step explanation:

Agustin Mateo and I tomorrow I'll training baseball cards Augustine has one fourth as many cars as Mateo Mateo have 1/2 as many cars as tomorrow who has more

Given that:

Number of cards tomorrow has = x

Number of cards Mateo has = 1/2 of tomorrow's cards = 1/2x = 0.5x

Number of cards Agustin has = 1/4 as many times as Mateo

Hence, Number of Agustin cards :

1/4 * 0.5x = 0.125x

Therefore,

Tomorrow's cards = x

Mateo's cards = 0.5x

Agustin cards = 0.125x

x > 0.5x > 0.125x

Hence,

Tomorrow has the most cards followed by Mateo, then Agustin

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In 2019, approximately 97.4% of all the runners who started the Boston Marathon (in Boston, Massachusetts, USA) were able to com
PtichkaEL [24]

Answer:

The probability that exactly 97 of them finished the marathon​ is 0.221.

Step-by-step explanation:

We are given that in 2019, approximately 97.4% of all the runners who started the Boston Marathon were able to complete the 42.2 km race.

100 runners are chosen at random.

The above situation can be represented through the binomial distribution;

P(X = x) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x = 0,1,2,3,......

where, n = number of trials(or samples) taken = 100 runners

           r = number of success = exactly 97

           p = probability of success which in our question is the probability

                 that runners finished the marathon​, i.e; p = 0.974

So, X ~ Binom(n = 100, p = 0.974)

Now, the probability that exactly 97 of them finished the marathon​ is given by = P(X = 97)

         P(X = 97) = \binom{100}{97} \times 0.974^{97} \times (1-0.974)^{100-97}

                          = 161700 \times 0.974^{97} \times 0.026^{3}

                          = 0.221

Hence, the required probability is 0.221.

6 0
3 years ago
Which is true about the completely simplified difference of the polynomials 6x6 − x3y4 − 5xy5 and 4x5y + 2x3y4 + 5xy5?
Galina-37 [17]
<span>Let be A= 6x6 − x3y4 − 5xy5 and B= 4x5y + 2x3y4 + 5xy5 and when we do their difference, it is A - B = 6x6 − x3y4 − 5xy5 -( 4x5y + 2x3y4 + 5xy5)=6x6 − x3y4 − 5xy5 - 4x5y - 2x3y4 - 5xy5 = 6x6 - x3y4 - 2x3y4 - 5xy5 -4xy5 -5xy5=6x6 - 3x3y4 -14xy5, so the final solution is A - B =6x6 - 3x3y4 -14xy5, the degree of this is equal to the degree of - 3x3y4, and it is 3+4=7, the answer is The difference has 3 terms and a degree of 7.</span>
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