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Margarita [4]
2 years ago
15

Agustin Mateo and I tomorrow I'll training baseball cards Augustine has one fourth as many cars as Mateo Mateo have 1/2 as many

cars as tomorrow who has more cards
Mathematics
1 answer:
Finger [1]2 years ago
7 0

Answer:

Tomorrow has the most cards followed by Mateo, then Agustin

Step-by-step explanation:

Agustin Mateo and I tomorrow I'll training baseball cards Augustine has one fourth as many cars as Mateo Mateo have 1/2 as many cars as tomorrow who has more

Given that:

Number of cards tomorrow has = x

Number of cards Mateo has = 1/2 of tomorrow's cards = 1/2x = 0.5x

Number of cards Agustin has = 1/4 as many times as Mateo

Hence, Number of Agustin cards :

1/4 * 0.5x = 0.125x

Therefore,

Tomorrow's cards = x

Mateo's cards = 0.5x

Agustin cards = 0.125x

x > 0.5x > 0.125x

Hence,

Tomorrow has the most cards followed by Mateo, then Agustin

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The sequence {an} is defined by a0 = 1 and
zavuch27 [327]
The solution to the problem is as follows:

Just plug in the numbers and follow the pattern. 

a0 = 1 

a1 = 2*1 + 2 = 4 

a2 = 2*4 +2 = 10 

<span>a3 = 2*10 +2 = 22
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I hope my answer has come to your help. God bless and have a nice day ahead!
5 0
3 years ago
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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
2 years ago
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Monica [59]
Hello,
Let's assume top left  corner: A
top right corner : B
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ABM is a triangle rectangular isocel:

(3√2)²+(3√2)²=y²
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x²+3²=(3√2)²
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8 0
3 years ago
Solve 14x + 1 = 36.<br> Round to the nearest ten-thousandth.
Aneli [31]

Answer:

x≈ 3.2056

Step-by-step explanation:

Set both sides by log.  Then, solve for x.

1. 14^(x + 1) = 36

(x + 1)log(14) = log(36)

x + 1 = log(36)/log(14) . . . Divide both sides by log(14)

x = log(36)/log(14) - 1 . . . . Subtract both sides by 1.

x ≈ 0.3579 . . . . . . . . . . . .Use calculator to simplify the expression.

Note that the second problem is similar  to the first.

2. 12^(y - 2) = 20

(y - 2)log(12) = log(20)

y - 2 = log(20)/log(12)

y = log(20)/log(12) + 2

y ≈ 3.2056

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3 years ago
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Answer:

47 if not

Step-by-step explanation:

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