Answer:
let c is a point between a and b we can find the coordinates of c by using mid-point formula
the coordinate x of c is equal to
x=(x1+x2)÷2
x=(3+27)÷2
x=30÷2
x=15
the coordinate y of c is equal to
y=(y1+y2)÷2
y=(2+30)÷2
y=32÷2
y=16
so the coordinates of c are (15,16)
Complete the square fr x and y's sepreatly to get into form
(x-h)²+(y-k)²=r²
the center is (h,k) and radius is r
so
group x's and y's seperatly
(4x²-10x)+(4y²+24y)+133/4=0
undistribute leading confident from each
4(x²-2.5x)+4(y²+6y)+133/4=0
take 1/2 of each linear confident and square it and add negative and positive inside the parenthasees
-2.5/2=-1.25 (-1.25)²=1.5625
6/2=3, 3²=9
4(x²-2.5x+1.5625-1.5625)+4(y²+6y+9-9)+133/4=0
factor perfect squares
4((x-1.25)²-1.5625)+4((y+3)²-9)+133/4=0
expand
4(x-1.25)²-6.25+4(y+3)²-36+133/4=0
4(x-1.25)²+4(y+3)²-9=0
add 9 to both sides
4(x-1.25)²+4(y+3)²=9
divide both sides by 4
(x-1.25)²+(y+3)²=9/4
(x-1.25)²+(y+3)²=(3/2)²
the center is (1.25,-3) and the radius is 1.5
Answer:
{t|<t<3}
Step-by-step explanation:
The domain of the relation represented by the graph is the time from 0 to 3 seconds the range of the relation is the heights from 0 to 64 feet.
