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3 years ago

I really need to know the answer

Mathematics

1 answer:

kramer3 years ago

4 0

We must follow order of operations rules (PEMDAS).

Thus, mult. and div. must be carried out before addn. and subtrn.

Calculate the quotient of (-2/5) and (4/5). In other words, divide (4/5) into (-2/5). Invert (4/5) and multiply:

(-2/5)(5/4) = -1/2

Then we have, in place of the original expression, the following expression:

-3/4 - 1/2 + (2 1/2).

Rewriting 2 1/2 as an improper fraction and elim. the parentheses yields:

-3/4 - 2/4 + 5/2, or -3/4 - 2/4 + 10/4, since the LCD is 4.

This yields 5/4 (answer)

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3 years ago

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B. How much information could be transmitted in 30,000 packets?

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2 years ago

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A laptop computer sells for $850. the sales tax is 7%. what is the total cost of the laptop?

evablogger [386]

Answer:

$909.50

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3 years ago

A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 70 p

nikklg [1K]

X = large boxes and y = small boxes

x + y = 70.....x = 70 - y
60x + 65y = 4300

60(70 - y) + 65y = 4300
4200 - 60y + 65y = 4300
5y = 4300 - 4200
5y = 100
y = 100/5
y = 20 <=== the small boxes weigh 20 lbs

x + y = 70
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x = 70 - 20
x = 50 <== and the large boxes weigh 50 lbs

5 0

3 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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3 years ago