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3 years ago

This equation has one solution. 5(r–1) + 3r =7(r + 1) What is the solution?

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

4 0

Answer:

R=12 is the solution

I don't know how to explain but it needs to be 20 characters

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Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

2 years ago

Find the equation of the line that passes through the points (-4,-2) and (-3,5) in both point-slope form and

kaheart [24]

<h2>Answer:</h2>

First, we must determine the slope, then we find the y-intercept using slope formula and slope-intercept form.

For slope:

$m = \frac{5 + 2}{-3 + 4} = \frac{7}{1} = 7$

Slope (m) = 7

For y-intercept:

$5 = 7(-3) + b\\\\5 = -21 + b\\\\26 = b$

Y-intercept (b) = 26

Using this information, we can now create the equations for this line.

$y= 7x + 26\\\\y - 5 = 7(x + 3)$

Formulas:

Slope formula: y₂ - y₁/x₂ - x₁

Slope-intercept form: y = mx + b

Point-slope form: y - y₁ = m(x - x₁)

*Note: (x₁, y₁), (x₂, y₂) = 2 points on the line

6 0

2 years ago

Does anyone know how to do this? Thanks!

Nataly [62]

C. 5

Step-by-step explanation:

The coeff of

${x}^{5}$

Is 15.

So by that we can write 3m = 15

m is 5.

8 0

2 years ago

Kelly buys a sweater for $16.79 and a pair of pants for $28.49. She pays with a $50 bill. How much change should Kelly get back?

andrew11 [14]

16.79+28.49=45.28

50-45.28=4.72

Kelly would get $4.75 back

4 0

2 years ago

Find the measure of each interior angle. Round to the nearest hundredth.

Butoxors [25]

Answer:

x = 76.80°

4x - 142 = 165.18°

x/5 = 15.36°

5x/9 + 60 = 102.66°

Step-by-step explanation:

Total angle in a quadrilateral is 360

x + 4x - 142 + x/5 + (5/9)x + 60 = 360

259x/45 + - 82 = 360

259x/45 = 442

x = 76.7953668

x = 76.80°

4x - 142 = 165.18°

x/5 = 15.36°

5x/9 + 60 = 102.66°

8 0

3 years ago