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natka813 [3]
3 years ago
5

Please help! i need this now!!!

Mathematics
1 answer:
ozzi3 years ago
7 0

Answer:

C

Step-by-step explanation:

Decimal Form:

197.98989873

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Zinaida [17]
You net worth will decrease because you’re paying a loan from the money that you have. While your net worth decreases your liabilities will decrease because you will no longer have a loan to pay for.
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3 years ago
Which rigid transformation(s) would map ΔJKL onto ΔPQR? a reflection only a rotation only a rotation and a reflection a translat
solniwko [45]

Step-by-step explanation:

A rigid transnformation is also know as isometrie. <u>This are transformations of the plane that preserves the lengths</u>. There are 3 types of isometries and each one can be combined with the others.

  • Reflection (First figure)
  • Translation (second figure)
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Combining this transformations you will be able to transform ΔJKL onto ΔPQR

6 0
3 years ago
Read 2 more answers
Step by step help for 17.5x2.48
kherson [118]
Start by writing it out like this:
  17.50
<u>*  2.48 </u> 
Make sure that all the places are in correct order. Notice that I added a ZERO in the place that had nothing there.
Move the decimal point so everything is a whole number. You have moved it 4 times.
Now, starting from 8, multiply it by 0, then 5, then 7, and lastly, 1. Now go to the next number (4) and do the same, this time though, put a zero in the first spot. Every new number, add another zero. 
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Your answer should be: 43.4

8 0
3 years ago
4sin²<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D" id="TexFormula1" title="\frac{x}{2}" alt="\frac{x}{2}" align="absm
raketka [301]

Answer:

\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}

Step-by-step explanation:

Hi there!

We want to solve for x in:

4\sin^2(\frac{x}{2})=3

Since x is in the argument of \sin^2, let's first isolate \sin^2 by dividing both sides by 4:

\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}

Next, recall that \sin^2x is just shorthand notation for (\sin x)^2. Therefore, take the square root of both sides:

\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}

Simplify using \displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}:

\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}

Let \phi = \frac{x}{2}.

<h3><u>Case 1 (positive root):</u></h3>

\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}

Therefore, we have:

\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}

<h3><u>Case 2 (negative root):</u></h3>

\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}

8 0
3 years ago
Growth mindset is a belief that intelligence can improve through________
RoseWind [281]

Answer:hard work

Step-by-step explanation:

Remember this from last year Lol

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3 years ago
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