The image of the question is attached below.
Given:
m∠DAC = 20° and m∠BCA = 30°
m∠ABC = 90° and m∠CDA = 90°
To find:
The value of x and y.
Solution:
In right triangle ABC,
m∠BAC = x° + 20°
Sum of the interior angles of a triangle = 180°
m∠BAC +m∠ABC + m∠BCA = 180°
x° + 20° + 90° + 30° = 180°
x° + 140° = 180°
Subtract 140° from both sides.
x° + 140° - 140° = 180° - 140°
x° = 40°
In right triangle ADC,
m∠ACD = y° + 30°
Sum of the interior angles of a triangle = 180°
m∠ACD +m∠CDA + m∠DAC = 180°
y° + 30° + 90° + 20° = 180°
y° + 140° = 180°
Subtract 140° from both sides.
y° + 140° - 140° = 180° - 140°
y° = 40°
The value of x is 40 and y is 40.
Answer:
1. (2+2)/(-3+4)= 4/1= 4
y + 2 = 4(x + 4)
y + 2 = 4x + 16
y = 4x + 14 y-intercept:(0,14)
2. (0+5)/(-1+2)= 5/1= 5
y + 5 = 5(x + 1)
y + 5 = 5x + 5
y = 5x
y-intercept (0,0)
3. (-1+1)/(-5-3)= 0/-8= 0
y + 1 = 0(x - 3)
y + 1 = 0
y= -1
Step-by-step explanation:
It's a proportion.
Here is your process:
15*4=60
60/20=3
3=y
:)
Step-by-step explanation:
25m + 10b = 400
not enough info to solve for m or b. but that's the equation you would use.
Answer:
happy birth day to me
Step-by-step explanation:
its F was i close