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nasty-shy [4]
2 years ago
12

Which table represents a linear function?

Mathematics
1 answer:
FromTheMoon [43]2 years ago
8 0

Answer:

A.

(1,3)

(2,7)

(3,11)

(4,15)

Step-by-step explanation:

I plotted the points into a graphing calculator

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What is the solución of the equation x2-4x+1=0?
koban [17]

Answer:

x = 2 + √3 and

x = 2 - √3

Step-by-step explanation:

Please use " ^ " to denote exponentiation:  x^2 - 4x + 1 = 0.

Here you have multiple choices of methods of solution:

quadratic formula, completing the square, graphing, and so on.

If we complete the square, then:                   x^2 - 4x + 1 = 0 becomes

                                                                       x^2 - 4x + 4 - 4 + 1 = 0, or

(x - 2)^2 = 3

Taking the square root of both sides, we get x - 2 = ±√3, so that the roots are:

x = 2 + √3 and

x = 2 - √3

6 0
3 years ago
Chris plans to buy a car that depreciates in value at a rate of 10% per year. If the car initially costs $32,000. How much will
VLD [36.1K]
The car would be worth $16,000 after 5 years.
5 0
3 years ago
Salina, Tamara, and Uma are working on their homework together. Salina tells her friends that she got θ=52∘θ=52∘ for the inverse
svlad2 [7]

Answer:

The values reported by Uma, Salina, and Tamara are all possible values for inverse cosine

Step-by-step explanation:

Solution:-

- The solution to the inverse "cosine" problem would have a general form:

                                    θ = cos^-1 ( a )

Where,  a: Any arbitrary constant, - 1 < a < 1

- The value of θ = 52° was reported by Salina suggests that the answer lies in the first quadrant of a cartesian plane where ( sin (θ) , cos (θ) , tan (θ) ) have positive values for "a".

Hence,                            0 < a < 1 , θ = 52°

- The value of θ = 128° was reported by Tamara suggests that the answer lies in the second quadrant of a cartesian plane where ( sin (θ) ) have positive values for "a" and (cos (θ) , tan (θ) have negative values for "a". So for cos (128):

Hence,                           -1 < a < 0 , θ = 128°

- The value of θ = 308° was reported by Uma suggests that the answer lies in the fourth quadrant of a cartesian plane where ( cos (θ) ) have positive values for "a" and (sin (θ) , tan (θ) have negative values for "a". So for cos (308):

Hence,                           0 < a < 1 , θ = 308°

- The angle θ reported by Uma and Salina are similar solution because of property law of complementary angles:

                                     cos (θ) = cos ( 360 - θ )

Where, θ = 52°,            cos (52°) = cos( 308°)  .. Uma and Salina conform

However,                      cos ( 180 - θ ) = - cos (θ)  

                                     cos(128) = - cos ( 52 ) .... Uma and Tamara conform.

5 0
3 years ago
Match the circle equations in general form with their corresponding equations in standard form. x2 y2 − 4x 12y − 20 = 0 (x − 6)2
frosja888 [35]

The equation given is matched with the respective vertex forms.

<h3>What is the standard Equation for a circle ?</h3>

The standard equation for a circle is given by

(x-h)² + (y-k)² = r²

The equation given in the question are

x² + y²  − 4x + 12y − 20 = 0

(x − 6)²  + (y − 4)²  = 56

x²  + y²  + 6x − 8y − 10 = 0

(x − 2)²  + (y + 6)²  = 60

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

5x²  + 5y²  − 10x + 20y − 30 = 0

(x+3)²  + (y-4)²  = 35

2x²  + 2y²  − 24x − 16y − 8 = 0

(x-1)²  + (y+2)²   = 11

The first equation is

x² + y²  − 4x + 12y − 20 = 0

It can be written ad

x² -4x + 4 - 4 +y²+12y +36-36 -20 = 0

(x-2)² +(y+6)²= 60

The second equation is

x²  + y²  + 6x − 8y − 10 = 0

x² +6x +9-9 +y²  -8y +16-16 -10 = 0

(x+3)²  + (y-4)²  = 35

The third equation is

3x²  + 3y²  + 12x + 18y − 15 = 0

(x + 2)²  + (y + 3)²  = 18

The fourth equation is

5x²  + 5y²  − 10x + 20y − 30 = 0

(x-1)²  + (y+2)²   = 11

The fifth equation is

2x²  + 2y²  − 24x − 16y − 8 = 0

(x − 6)²  + (y − 4)²  = 56

To know more about standard equation of Circle

brainly.com/question/13658927

#SPJ1

7 0
1 year ago
Ax:ab =1:3 where is x
zimovet [89]
X is in your phone duhh
5 0
2 years ago
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