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goldenfox [79]
3 years ago
9

Need fast Help please ! Click on the picture

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
ABC ~ A’B’C’

So, AB=A’B’ , BC=B’C’ , AC = A’C’

Given, AB=15 and A’C’=4

So, AC = 4 , A’B’ = 15
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What is the end behavior of the polynomial function graphed below?
Afina-wow [57]

Answer:


Step-by-step explanation:

The answer is C

5 0
3 years ago
Evaluate the piecewise-defined function for the indicated values. I’m just unsure of how to solve when the value isn’t given dir
Fantom [35]

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for m^{2} +1 is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and \sqrt{t-1} for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at m^{2} +1 when m belongs to \sqrt{7} and \sqrt{10} the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

Learn more about functions at brainly.com/question/10439235

#SPJ10

6 0
2 years ago
If f(x)=-4x^2-6x-1 and g(x)=-x^2-5x+3, fine (f-g)(x)
NeX [460]

Answer:

\large\boxed{(f-g)(x)=-3x^2-x-4}

Step-by-step explanation:

(f-g)(x)=f(x)-g(x)

f(x)=-4x^2-6x-1,\ g(x)=-x^2-5x+3\\\\(f-g)(x)=(-4x^2-6x-1)-(-x^2-5x+3)\\\\(f-g)(x)=-4x^2-6x-1-(-x^2)-(-5x)-3\\\\(f-g)(x)=-4x^2-6x-1+x^2+5x-3\qquad\text{combine like terms}\\\\(f-g)(x)=(-4x^2+x^2)+(-6x+5x)+(-1-3)\\\\(f-g)(x)=-3x^2-x-4

5 0
3 years ago
You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y
KonstantinChe [14]

Answer:

752.95

Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

= 1.96^2\times \frac{210^2}{15^2}

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come

8 0
3 years ago
Which of the following is the scatter plot of the data below?
soldier1979 [14.2K]
If you look at the points, you can find out
4 0
3 years ago
Read 2 more answers
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